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marin [14]
3 years ago
12

You are planning on using circles to compare the populations of California 37,691,000, Texas 25,675,000, and New York 19,465,000

. If the circle for New York will have a 5 cm radius, how large should the radii for Texas and California be? Round to the nearest tenth of cm
Mathematics
1 answer:
Alina [70]3 years ago
3 0
\bf \begin{array}{ccllll}
population&radius\\
-----&-----\\
19465000&5\\
25675000&t
\end{array}\implies \cfrac{19465000}{25675000}=\cfrac{5}{t}\impliedby texas
\\\\\\
\begin{array}{ccllll}
population&radius\\
-----&-----\\
19465000&5\\
37691000&c
\end{array}\implies \cfrac{19465000}{37691000}=\cfrac{5}{c}\impliedby california

solve for "t" and "c" respectively
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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.
const2013 [10]

Answer:

a.

T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

b.

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

Step-by-step explanation:

Remember that for any curve      r(t)  

The tangent vector is given by

T(t) = \frac{r'(t) }{| r'(t)| }

And the normal vector is given by

N(t) = \frac{T'(t)}{|T'(t)|}

a.

For this case, using the chain rule

r'(t) = (  -10*2tsin(t^2) ,   102t cos(t^2)   )\\

And also remember that

|r'(t)| = \sqrt{(-10*2tsin(t^2))^2  +  ( 10*2t cos(t^2) )^2} \\\\       = \sqrt{400 t^2*(  sin(t^2)^2  +  cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t

Therefore

T(t) = r'(t) / |r'(t) | =  (  -10*2tsin(t^2) ,   10*2t cos(t^2)   )/ 20t\\\\ = (  -10*2tsin(t^2)/ 20t ,   10*2t cos(t^2) / 20t  )\\= ( -sin(t^2), cos(t^2) )

Similarly, using the quotient rule and the chain rule

T'(t) = ( -2t cos(t^2) , -2t sin(t^2))

And also

|T'(t)| = \sqrt{  ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t

Therefore

N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

Notice that

1.   |N(t)| = |T(t) | = \sqrt{ cos(t^2)^2  + sin(t^2)^2 } = \sqrt{1} =  1

2.   N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0

b.

Simlarly

r'(t) = (2t,-6,0) \\

and

|r'(t)| = \sqrt{(2t)^2   + 6^2} = \sqrt{4t^2   + 36}

Therefore

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

Then

T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)

and also

|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 +   ( (3 t)/(9 + t^2)^{3/2})^2  +  0^2 }\\= 3/(t^2 + 9 )

And since

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

6 0
3 years ago
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abruzzese [7]

Answer:

They want the flat to be lower than the 5th floor. They want a flat that costs between £875 and £925 per month. Riya finds information about flats to rent.

Step-by-step explanation:

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8 0
3 years ago
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Volgvan
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5 0
3 years ago
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Belle borrowed $18.275 to buy a new car. The interest rate she agreed to pay is 5%. If she takes 5 years to pay back the loan, h
mamaluj [8]

Answer:

$22843.75

Step-by-step explanation:

I'm assuming that $18.275 is $18,275

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 18275 × 0.05 × 5 = 4568.75

I = $ 4,568.75

The simple interest accumulated

on a principal of $ 18,275.00

at a rate of 5% per year

for 5 years is $ 4,568.75.

4 0
3 years ago
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A triangle has angle measures of 47 degrees and 92 degrees. What is the measure of the third angle?
ludmilkaskok [199]

Answer:

The missing angle is 41 degrees

Step-by-step explanation:

First of all, a triangle is measured at 180 degrees in total

To find the missing measurement for the third angle, add the 47 and 92 degrees together which would equal 139 degrees.

47+92=139 degrees

Next just subtract 139 from 180 to get your answer.

180-139=41 degrees

The answer is 41 degrees

<u><em>Hope this helps</em></u>

5 0
3 years ago
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