Answer:
±6
Step-by-step explanation:
Given the mathematical expression;
√36 < √42 < √49
But, √36 = 6 * 6 = 6²
√49 = 7 * 7 = 7²
Simplifying further, we would substitute the new values respectively;
±[6] < √42 < ±[7]
Therefore, evaluating √36 is equal to ±6.
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
0.349
Step-by-step explanation:
Answer:
85.9 m
Step-by-step explanation:
The law of sines can help figure this.
The remaining angle in the triangle is ...
180° -75° -68° = 37°
This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...
b/sin(B) = c/sin(C)
b = sin(B)·c/sin(C) = 132.3·sin(37°)/sin(68°) ≈ 85.873 . . . meters
The surveyor is about 85.9 meters from the second marker.
