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3 years ago

Type the correct answer in the box. Round your answer to two decimal places.

Mathematics

2 answers:

kondor19780726 [428]3 years ago

5 0

Answer:

1.29

Step-by-step explanation:

sine23=x/3.3

svp [43]3 years ago

3 0

Angle TRQ is 23 degrees and the length from S to R is 3.3 units.

I need help on this too

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Kaitlin drove 936 miles in 13 hours.

sergij07 [2.7K]

Answer:

756 miles

Step-by-step explanation:

Divide 936 by 13 to get 72, the miles per hour and then multiply by 8

5 0

3 years ago

The box plots below show the lifespan, in months, of laptop batteries manufactured by four companies:

melomori [17]

I see 2 answers here. Company C and D at 8 months... (Companies A and B at 5 months)

Explanation:

I took the Maximum and subtracted it by the Minimum.

Ex. Company D: 27 (Max) - 19 (Min) = 8 months

8 0

2 years ago

Cos^2x+4cosx+4/cosx+2=2secx+1/secx

Lorico [155]

Answer:

$\frac{\cos^2x+4\cos x+4}{\cos x+2}=\frac{2\sec x+1}{\sec x}$

Step-by-step explanation:

To prove the given identity, we solve the left hand side and right hand side expressions and show that they are equal.

So we get $\frac{2\sec x+1}{\sec x}\\\\=\frac{2\sec x}{\sec x}+\frac{1}{\sec x}\\\\= 2+\cos x\\\\\text{since the left hand side and right hand side expression are same, so}\\\text{it verifies the identity.}$

$\text{Left hand side}=\frac{\cos^2x+4\cos x+4}{\cos x+2}\\\\\text{Here observe that the numerator is a perfect square using }\\a^2+2ab+b^2=(a+b)^2\\\text{so we get}\\\\=\frac{(\cos x+2)^2}{\cos x+2}\\\\\text{now we can cancel out one factor (cos x+2) from numerator and denominator.}\\\text{so we get}\\\\=\cos x+2\\\\\text{And similarly the right hand side gives}$

7 0

3 years ago

Which of the following tables does NOT define a function?

madreJ [45]

Answer:

Step-by-step explanation:

doesnt define a function

5 0

3 years ago

Read 2 more answers

How can you use a mapping diagram to determine the domain and the range of a relation?

Studentka2010 [4]

Step 1: Draw the mapping diagram for the given relation.
Step 2: A relation is a function if each element in the domain is paired with one and only one element in the range.
<span>Step 3: From the mapping diagram, it can be observed that the given relation is not a function as '3' in the domain is paired with two elements - 1 and - 2 in the range and '6' is paired with - 1 and - 2.

  Domain Range
    3   | -1
|
|
  6    |   -2</span>

4 0

3 years ago