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mr_godi [17]
3 years ago
8

Please please help!! Quickly

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0

Answer:

pretty sure its D

dem82 [27]3 years ago
3 0

Answer:

I have to give 2 Ans for my question

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Help asap neeed help
dalvyx [7]
It’s the last one. Six.

Explanation: 6*6 = 36 - 3 = 33 > 21
3 0
3 years ago
Leslie ran 4 1/2 laps around the park in 3/4 hour. Kayla ran 3 1/2 laps around the same park in the same amount of time. How man
Arte-miy333 [17]
Leslie:
h= hours
3/4h=4 1/2 laps
divide both sides by 3/4 or .75
1 hour = 6 laps
Kayla:
3/4h= 3 1/2 laps
divide both sides by 3/4
1 hour = 4 2/3 laps
Leslie can do C
1_ 1/3 more laps in an hour than Kayla
5 0
3 years ago
How days Feb 7 through Dec 23 or to Feb 7?
miv72 [106K]
319 days to feb 10 months and 16days 
4 0
3 years ago
Sasha is the manager at a factory.
FromTheMoon [43]

Answer:

Hi

I think the answer is 80 employees.

Step-by-step explanation:

15 employees - 390 wardrobes

Therefore 1200 divided by 15 equals 80

7 0
3 years ago
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
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