Answer
<span>D) Any point on a perpendicular bisector is equidistant from each endpoint of the line segment.
Explanation.
A perpendicular bisector, divides the line segment in to two equal parts. It should be perpendicular to the line segment.
The best description the </span><span>the construction of a perpendicular bisector is the one that talks of a general points that lies along the perpendicular bisector and are equidistant from the two ends. From the choices the answer is; </span><span>Any point on a perpendicular bisector is equidistant from each endpoint of the line segment.</span>
Answer:
Radius = 2.90 cm
Step-by-step explanation:

220 = 3.14 × {r}^{2} × 8.3
220 = 26.062 × {r}^{2}
220/26.062 = {r}^{2}
{r}^{2} = 8.44 ( approx )
r = √8.44
r = 2.90 cm. (approx)
Hope this helps .....
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Answer:
18
Step-by-step explanation:
When x equals -3, then the first equation is simplified to 9 + 6 + 3 = 18; and the second equation confirms the same answer by showing -6 x -3 = 18
Answer:
thank you for this warning
Step-by-step explanation:
ive been getting these alot lately!!
Given the equation:

We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3