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Serjik [45]
3 years ago
12

4m-3/4=-9+4m/8 this is my question that i need help with

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

Answer:

m=-\frac{33}{14}

Step-by-step explanation:

4m-\frac{3}{4}=-9+\frac{4m}{8}

(4m-\frac{3}{4})8=(-9+\frac{4m}{8})8 multiply by 8 to get rid of the largest denominator

32m-\frac{24}{4}=-72+4m

32m-6=-72+4m

32m-4m=-72+6 Rearrange the equation and Collect like-terms

28m=-66

m=-\frac{66}{28} simplify

m=-\frac{33}{14}

Bess [88]3 years ago
5 0

Answer:

The answer is -2 5/14 if you're trying to solve for m

Step-by-step explanation:

first you get rid of the fractions by mutiplying both sides by 4.

4(4m-3/4)=(-9+4m/8)4

16m-3=-36+2m      then you put the varible terms on one side and the numbers on one side

14m=-33

then divide -33 by 14

which will give you the fraction -2 5/14 unless you want decimal form which would be around -2.36

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A or B (It can be any)

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3 years ago
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E and f are supplementary. the measure of e is 54 more than the measure of f. find the measures of each angle.
Katen [24]
Supplementary means they add up to 180

X + 54 = 180

180-54= x

X = 126

126+54=180?

Yep

So your answer is

126
6 0
3 years ago
What’s the slope intercept form of (2,5) and (0,1)
Travka [436]

Answer:

y=2x+1

Step-by-step explanation:

First you have to find the slope:

5-1/2 so 4/2 or 2

Then you write it in point-slope: (I used the point (0,1))

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8 0
4 years ago
If f(x) = 2x – 6 and g(x) = x – 22, find each value.
Charra [1.4K]

Answer:

Step-by-step explanation:

I think you made a typo. g(x) should equal x - 2 not x - 22

g(x) =  x - 2

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7 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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