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3 years ago

Uhhh what????????????

Mathematics

2 answers:

nalin [4]3 years ago

8 0

Calculate volumes

v=lwh
vinitial=6*5*5=150
vnew=6*15*15=1350

new/initial=1350/150=9

9 times

Hunter-Best [27]3 years ago

4 0

Answer:

i don't understand lol

Sincerely, Now feeling dumb me

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A group of people were asked if they had run a red light in the last year. 385 responded "yes", and 472 responded "no".

Dimas [21]

Answer:

44.9%

Step-by-step explanation:

you can find the probability by dividing the total number of people by the number of people who have run a red light:

385/857

simplify into a decimal:

0.449

convert into a percent to get your answer:

44.9%

3 0

2 years ago

What is the equation of the line graphed below?

vesna_86 [32]

Answer:

The answer to your question is: letter B

Step-by-step explanation:

Data

A (-5, 4)

B (4, 1)

Formula

slope = m = $\frac{1 - 4}{4 + 5}$

m = $\frac{-3}{9}$ = $\frac{-1}{ 3}$

Point slope

(y - 4) = $\frac{-1}{3}$ (x + 5)

4 0

2 years ago

Given that R = 4 x + 8 y Find y when x = 4 and R = 32

victus00 [196]

R = 4 x + 8y [ Given ]

when ,

x = 4 and R = 32

★ Substituting the values

=> 32 = 4 × 4 + 8y

=> 32 = 16 + 8y

=> 8y = 32 - 16

=> 8y = 16

=> y = 8/16

=> y = 2

7 0

3 years ago

Read 2 more answers

9.433 9.4 9.37 9.311 9.345 9.35 Least to greatest

faust18 [17]

Answer:

LEAST

9.311

9.345

9.35

9.37

9.4

9.433

GREATEST

Step-by-step explanation:

plz mark brainliest! :)

5 0

2 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

2 years ago