Answer:
17
Explanation:
Step 1: Calculate the needed concentrations
[A]i = 1.00 mol/5.00 L = 0.200 M
[B]i = 1.80 mol/5.00 L = 0.360 M
[B]e = 1.00 mol/5.00 L = 0.200 M
Step 2: Make an ICE chart
A(aq) + 2 B(aq) ⇄ C(aq)
I 0.200 0.360 0
C -x -2x +x
E 0.200-x 0.360-2x x
Then,
[B]e = 0.360-2x = 0.200
x = 0.0800
The concentrations at equilibrium are:
[A]e = 0.200-0.0800 = 0.120 M
[B]e = 0.200 M
[C]e = 0.0800 M
Step 3: Calculate the concentration equilibrium constant (K)
K = [C] / [A] × [B]²
K = 0.0800 / 0.120 × 0.200² = 16.6 ≈ 17
Complete Question
The complete question is shown on the first uploaded image
Answer:
The consumption of the reactant benzophenone and the production of triphenylmethanol can be detected using their IR absorption spectrum
This reaction is shown on the second uploaded image
The reactant benzophenone is a compound which contains a carbonyl functional group, and the stretching frequency of C=O bond has a high absorption at around
and frequency band of this wavelength is absent in triphenylmethanol.
in the same vain the product triphenylmethanol is a compound which contains a hydroxyl (OH) functional group, and the stretching frequency of O-H bond has a high absorption at around
and frequency band of this wavelength is absent in benzophenone.
To use infrared spectroscopy to show that the reaction is occurring is to show the disappearance of the
frequency band which indictes the consumption of benzophenone and the appearance
frequency band which indictes the formation of triphenylmethanol
Explanation:
Answer: 2.54g
Explanation:
Molar Mass of H2O2 = (2x1) + (2x16) = 34g/mol
1mole (34g) of H2O2 contains 6.02x10^23 molecules
Therefore Xg of H2O2 will contain 4.5x10^22 molecules i.e
Xg of H2O2 = (34x4.5x10^22)/6.02x10^23 = 2.54g
Answer:
<h3>F=4k.gm/s^2</h3>
Explanation:
<h3>F=m×a</h3><h3>f=2k.g×2m/s^2</h3><h3>f=4k.gm/s^2</h3>
Answer:
164
1st step we will write desperate molar mass of each element