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sergiy2304 [10]
3 years ago
5

What is the percent by mass of carbon in acetone c3h6o

Chemistry
2 answers:
Volgvan3 years ago
7 0

Well, the molar mass of acetone would be

3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.

out of this total, 3(12.011), or 36.033 grams are carbon

So, to find the percent, you do part over whole

36.033/58.08, which equals 0.6204 with significant figures

multiply that by 100 to get 62.04%

Hope that helps!

klio [65]3 years ago
6 0

Answer:

62.07% is the percent by mass of carbon in acetone.

Explanation:

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100

Molar mass of acetone =58 g/mol

Number of carbon atom in acetone = 3

Atomic mass of carbon = 12 g/mol

Percentage of carbon in acetone:

\frac{3\times 12 g/mol}{58 g/mol}\times 100=62.07\%

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A change in matter that produces new substances is called a _____. 1.mixture 2.physical change 3.solution 4.chemical change
12345 [234]

Answer:

Chemical Change

Explanation:

chemical bonds within the substance have been altered because a new substance has been produced. It cannot be a mixture because they do not involve changes in matter, it cannot be a physical change because they do not result in new substances, it is not a solution because those do not involve changes in matter.

7 0
3 years ago
Consider the resonance structures of formate. the first lewis structure of formate has a central carbon atom. a hydrogen atom an
OleMash [197]
So,

Formate has a resonating double bond.

In molecular orbital theory, the resonating electrons are actually delocalized and are shared between the two oxygens.  So the carbon-oxygen bonds can be described as 1.5-bonds (option B).  I'm not sure if option C is correct, however, because the likelihood of both delocalized electrons being in the area of one oxygen atom is less than 50%.<span />
6 0
3 years ago
How many N2 molecules would exist in 500g of water at 20C?
tankabanditka [31]

We have to know the number of molecules present in 500 g of water.

The answer is: zero molecules present in 500g of water.

Water molecule is H₂O. In water molecule, nitrogen molecule can not be present. Molecular mass of water is 18 g. MOlecular mass of nitrogen molecule is 28 g.

500 g water contains 500/18 number of moles= 27.77 moles of water molecules which contains 27.77 X 6.023 X 10²³ number of water molecules.

There is no existence of N₂ molecule.

6 0
3 years ago
Name this compound:<br> -Using E/Z designation<br> -Using Cis/Trans designation
vekshin1

Answer:

A:  (Z)-3-chloro-4-ethyl-2,5-dimethyl-3-hexene

B: (<em>cis</em>)-3-chloro-4-ethyl-2,5-dimethyl-3-hexene

Explanation:

                   The two two heavier groups around the double bond are chlorine and isopropyl.

                    Both of these heavier groups are on the same side therefore, they are designated as cis or Z conformer.

3 0
3 years ago
In a Dam, If we doubled the depth of the dam the hydrostatic force will be ?
AnnZ [28]

Answer: Option (A) is the correct answer.

Explanation:

Force acting on a dam is as follows.

                  F = \frac{1}{2}\rho g\omega H^{2} .......... (1)

Now, when we double the depth then it means H is increasing 2 times and then the above relation will be as follows.

                F' = \frac{1}{2}\rho g\omega (2)^{2}

               F' = \frac{1}{2}\rho g\omega 4 ........... (2)

Now, dividing equation (1) by equation (2) as follows.

          \frac{F}{F'} = \frac{\frac{1}{2}\rho g\omega H^{2}}{\frac{1}{2}\rho g\omega 4}  

Cancelling the common terms we get the following.

                 \frac{F}{F'} = \frac{1}{4}    

                   4F = F'

Thus, we can conclude that if doubled the depth of the dam the hydrostatic force will be 4F.

4 0
3 years ago
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