Question

What is the percent by mass of carbon in acetone c3h6o

Answer 1

Well, the molar mass of acetone would be

3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.

out of this total, 3(12.011), or 36.033 grams are carbon

So, to find the percent, you do part over whole

36.033/58.08, which equals 0.6204 with significant figures

multiply that by 100 to get 62.04%

Hope that helps!

Answer 2

Answer:

62.07% is the percent by mass of carbon in acetone.

Explanation:

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100$

Molar mass of acetone =58 g/mol

Number of carbon atom in acetone = 3

Atomic mass of carbon = 12 g/mol

Percentage of carbon in acetone:

$\frac{3\times 12 g/mol}{58 g/mol}\times 100=62.07\%$