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Tpy6a [65]
4 years ago
7

Given that the density of iron is 7.9 g/cm3, what would be the volume of a 15.8 g piece of iron

Chemistry
1 answer:
Anuta_ua [19.1K]4 years ago
7 0

Answer:

2cm^3

Explanation:

Use the density triangle: D=MxV

Switch for variables, V=M/D

Plug in numbers, 15.8g/7.9g/cm^3=2cm^3

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The initial concentration of solution is 0.0693 M. The volume of solution taken is 10 mL and it is diluted to a final volume of 500 mL.

According to dilution law, the product of initial concentration and volume is equal to the product of final concentration and volume as follows:

C_{1}V_{1}=C_{2}V_{2}

Here, C_{1} is initial concentration, C_{2} is final concentration, V_{1} is initial volume and V_{2} is final volume.

Rearranging to calculate final concentration,

C_{2}=\frac{C_{1}\times V_{1}}{V_{2}}

Putting the values,

C_{2}=\frac{0.0693 M\times 10 mL}{500 mL}=0.001386 M

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