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zubka84 [21]
3 years ago
7

What is the molar mass of tin (II) sulfate?

Chemistry
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

214.77 g/mol

Explanation:

Tin(II) sulfate

From Wikipedia, the free encyclopedia

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Tin(II) sulfate

Tin(II) sulfate crystallizes in an heavily distorted barium sulfrate structure.

Unit cell of tin(II) sulfate.

Names

Other names

Stannous sulfate

Identifiers

CAS Number  

7488-55-3 ☑

3D model (JSmol)  

Interactive image

ChemSpider  

21106484 ☑

ECHA InfoCard 100.028.457 Edit this at Wikidata

EC Number  

231-302-2

PubChem CID  

62643

UNII  

0MFE10J96E ☑

CompTox Dashboard (EPA)  

DTXSID20884389 Edit this at Wikidata

InChI[show]

SMILES[show]

Properties

Chemical formula SnSO4

Molar mass 214.773 g/mol

Appearance white-yellowish crystalline solid

deliquescent

Density 5.15 g/cm3

Melting point 378 °C (712 °F; 651 K)

Boiling point decomposes to SnO2 and SO2

Solubility in water 33 g/100 mL (25 °C)

Structure[1]

Crystal structure Primitive orthorhombic

Space group Pnma, No. 62

Lattice constant  

a = 8.80 Å, b = 5.32 Å, c = 7.12 Å[2]

Hazards

NFPA 704 (fire diamond)  

NFPA 704 four-colored diamond

010

Flash point Non-flammable

Lethal dose or concentration (LD, LC):

LD50 (median dose) 2207 mg/kg (oral, rat)

2152 mg/kg (oral, mouse)[3]

Related compounds

Other anions Tin(II) chloride, tin(II) bromide, tin(II) iodide

Other cations Lead(II) sulfate

Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Tin(II) sulfate (SnSO4) is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence. It can be prepared by a displacement reaction between metallic tin and copper(II) sulfate:[4]

Sn (s) + CuSO4 (aq) → Cu (s) + SnSO4 (aq)

Tin(II) sulfate is a convenient source of tin(II) ions uncontaminated by tin(IV) species.

34kurt3 years ago
7 0
Answer:
214.77 g/mol
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 the  mass  of  potassium iodide  is  0.360  g


calculation

 step 1:  write the balanced molecular  equation

Pb(NO3)2  (aq)  + 2 Ki (s)→ Pbi2(s)  + 2KNO3

step 2 ; calculate the  moles of Pbi2

moles =  mass /molar mass

= 0.500 g / 461 .0  g/mol  =0.0011 moles


step  3:  use the mole ratio to  calculate  the  moles of Ki

Ki: Pbi2  is  2:1  therefore  the  moles of  ki  = 0.0011  x 2/1 =  0.0022  moles


step 4 :  find the mass of Ki

mass=  moles  x molar  mass

=0.0022  moles  x 166g/mol  =0.365  g  which is  approximate  0.360 g


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