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professor190 [17]
3 years ago
8

Find the value of x for which

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
B


hope this helps :)
(can you please mark me as brainliest?)
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The graph that represents the system of inequalities is graph 3
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3 years ago
Read 2 more answers
In 1990, Dawn gross pay was $48,000.
forsale [732]

A. Dawn's gross monthly pay is<em> $4,000</em> ($48,000/12).

B. The month that Dawn hit her maximum taxable Social Security Income is May (5 months from January to May).

C. In February, 1978, Dawn paid <em>$260</em> in Social Security Tax.

D. In May, 1978, Dawn paid <em>$110.50</em> in Social Security Tax, which represented the balance.

E. In November, 1978, Dawn paid <em>$0</em> in Social Security Tax because by May she had completely paid the maximum Social Security Tax of $1,150.50.

<h3>Data and Calculations:</h3>

Gross earnings in 1990 = $48,000

Maximum taxable income in 1990 = $17,700

Social Security Tax Rate = 6.5%

Gross monthly pay = $4,000 ($48,000/12)

Monthly Social Security Tax = $260 ($4,000 x 6.5%)

Total Social Security Tax = $1,150.50 ($17,700 x 6.5%)

In 5 months, Dawn would have paid a <em>total of $1,150.50</em> ($260 x 4 + $110.50) in Social Security Tax.

Thus, the total Social Security Tax paid by Dawn in that year was <em>$1,150.50.</em>

Learn more about Social Security Tax here: brainly.com/question/9741758

4 0
2 years ago
ILL GIVE BRAINLIEST!!
densk [106]

Answer:

P(3 , 0)

Step-by-step explanation:

(x₁, y₁) = A(-3,-3)    ;(x₂ , y₂) B(5, 1)

m : n = 3 : 1

P \left( \dfrac{mx_{2}+nx_1}{m+n},\dfrac{my_{2}+ny_{1}}{m+n} \right)\\\\P \left (\dfrac{5*3+(-3)*1}{3+1},\dfrac{3*1+1*(-3)}{3+1} \right)\\\\\\=P \left(\dfrac{15-3}{4},\dfrac{3-3}{4} \right)\\\\\\= P \left(\dfrac{12}{4},\dfrac{0}{4} \right)\\\\\\= P\left(3 , 0 \right)

5 0
2 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

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3 years ago
What is the diagonal of a 16×12 inch tv
mamaluj [8]

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the diagonal of TV equal to 20

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