It is 30-60-90 triangle, so:

Answer B.
Answer:
87.73 inches
Step-by-step explanation:
We are given that the dimensions of the rectangular doorway are,
Length = 6 ft 8 inches = 80 inches and Width = 3 feet = 36 inches.
Using Pythagoras Theorem, we will find the diagonal of the rectangular doorway.
i.e. 
i.e. 
i.e. 
i.e. 
i.e. Hypotenuse = ±87.73 inches
Since, the length cannot be negative.
So, the length of the diagonal is 87.73 inches.
As, the largest side of a rectangle is represented by the diagonal.
So, the largest dimension that will fit through the doorway without bending is 87.73 inches.
Answer:
one solution is (0, -2)
Step-by-step explanation:
The line y = -x is the boundary of the solution space of the first inequality. The less-than symbol (<) tells you that the line will be dashed and the shading will be below it. The line has a slope of -1 and goes through the y-intercept point (0, 0).
The line y = x - 2 is the boundary of the solution space for the second inequality. The less-than-or-equal-to symbol (≤) tells you the line will be solid (or equal to) and the shading will be below it (less than). The line has a slope of +1 and goes through the y-intercept point (0, -2).
The area of the graph where the shadings overlap is the solution space for the system of inequalities. Any point in that area will do, including points on the solid line where y < -x. (0, -2) is one such point.
If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)