<span><span>evil can be another word for Iniquitous</span></span>
Answer:
Don’t ask me over for tea. I take my rhyme straight, just like my drink, delivered by Willie or Merle.
Explanation:
Don’t ask me over for tea. I take my rhyme straight, just like my drink, delivered by Willie or Merle.
Answer:
i want points so me take points HAHAHA
Explanation:
Let s(i),k denote the substring s(i)s(i+1)...s k. Let Opt(k) denote whether the sub-string s1,k can be segmented using the words in the dictionary, namely (k) =1 if the segmentation is possible and 0 otherwise. A segmentation of this sub-string s1,k is possible if only the last word (say si k) is in the dictionary theremaining substring s1,i can be segmented.
Therefore, we have equation:Opt(k) = max Opt(i) 0<i<k and s(i+1),kis a word in the dictionary
We can begin solving the above recurrence with the initial condition that Opt(0) =1 and then go on to comput eOpt(k) for k= 1, 2. The answer correspond-ing to Opt(n) is the solution and can be computed in Θ(n2) time.
The best choice is option one, although that is not fully correct. But because an author is present, the name comes first.