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igor_vitrenko [27]
3 years ago
9

A giraffe would not be able to survive in a city due to the a0 factors such as buildings, streets, and sewage.

Chemistry
2 answers:
My name is Ann [436]3 years ago
8 0
Is This True Or False ? If So This Is True 
Hope This Helps !
- TyyBenjii
Mars2501 [29]3 years ago
3 0
Due to the EVIRONMENTAL factors of the city, the giraffe wouldn't be able to adapt. Hope this helps! :)
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A divergent boundary is when two tectonic plates move apart from one another.

8 0
3 years ago
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Help me with questions 1-8. here's the link to the textbook
Ede4ka [16]

Answer:

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Explanation:

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6 0
3 years ago
NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc​
eduard

\tt Kp=Kc(RT)^{\Delta n}

NH₄Cl (s) ⇔ NH₃ (g) + HCl (g)

Δn = 2 (gas only)

R = 0.082

T = 427 + 273 = 700 K

4.8 = Kc (0.082 x 700)²

Kc = 1.45 x 10⁻³

7 0
2 years ago
How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

3 0
3 years ago
El osmio es un metal sólido que tiene una densidad
pentagon [3]

Respuesta:

4.42 × 10⁻⁶ m³

Explicación:

Paso 1: Información provista

  • Densidad del osmio (ρ): 22600 kg/m³
  • Masa de osmio (m): 100 g

Paso 2: Convertir 100 g a kilogramos

Usaremos el factor de conversion 1 kg = 1000 g.

100 g × 1 kg/1000 g = 0.100 kg

Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio

La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.

ρ = m/V

V = m/ρ

V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³

5 0
3 years ago
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