1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igor_vitrenko [27]
3 years ago
9

A giraffe would not be able to survive in a city due to the a0 factors such as buildings, streets, and sewage.

Chemistry
2 answers:
My name is Ann [436]3 years ago
8 0
Is This True Or False ? If So This Is True 
Hope This Helps !
- TyyBenjii
Mars2501 [29]3 years ago
3 0
Due to the EVIRONMENTAL factors of the city, the giraffe wouldn't be able to adapt. Hope this helps! :)
You might be interested in
What is the enthalpy change (in kj) of a chemical reaction that raises the temperature of 250.0 ml of solution having a density
Pepsi [2]
<span>250 ml * 1.25 g/ml * 3.74 j/g-K * 9.2 K = 10.752 kJ Pretty much, all you need to do here is multiply all of these out to get your final answer. Not all questions are this easy, but this is certainly one of them.</span>
3 0
3 years ago
Read 2 more answers
When acids react with water, ions are released which then combine with water molecules to form .
mestny [16]
When acids react with water, H ions are released which then combine with water molecules to form H₃O⁺
7 0
4 years ago
Read 2 more answers
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 Cm^{3}

First, find the Density of given substance.

Formula used :    

Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}

Now,put all the values in this formula, we get

Density=\frac{46.9 g}{3.5 Cm^{3} } = 13.4 g/Cm^{3}

So, we conclude that the density of given substance (13.4 g/Cm^{3}) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/Cm^{3} respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

3 0
3 years ago
Read 2 more answers
What provides the energy to set the water cycle in motion?
romanna [79]
Where is the question
7 0
3 years ago
List a mixture that can be separated by fractional distillation
vivado [14]
Separation of components of crude oil
5 0
3 years ago
Other questions:
  • How does the internal structure of the Earth affect the surface of the planet?
    5·1 answer
  • An atom of iron has the atomic number 26 and a mass number of 56. how many protons plus neutrons are in the nucleus?
    11·2 answers
  • What accident led percy julian to discover the method to separate progesterone from soybean oil?
    12·1 answer
  • Multiple Questions, Brainliest and 98 points to whoever answers all questions correctly
    10·2 answers
  • Calculate the molar mass of Cr4(P2O7)
    5·1 answer
  • Calculate the mass percent of titanium in the mineral ilmenite, FeTiO3. What mass of ilmenite (in grams) is required if you wish
    9·1 answer
  • for every 10 yards on a football field there I boldly marked line labeled with the amount of yards there are two parallel sideli
    7·1 answer
  • The following reaction establishes equilibrium at 2000 K: If the reaction began with 0.110 of and 0.110 of , what were the equil
    7·1 answer
  • Find the odd one out of --retina,cochlea,ciliary muscles,cornea​
    8·1 answer
  • What are the two elements sand is made of? *
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!