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AVprozaik [17]
3 years ago
14

What type of reaction always takes one large molecule and breaks it down into its smaller pieces?

Chemistry
1 answer:
Ugo [173]3 years ago
8 0

Answer:

The answer to your question is the letter D. a decomposition reaction

Explanation:

This is a brief description of the main chemical reactions.

a) A synthesis reaction is when two reactants are combined to form only one product.

b) A disynthesis reaction. I have not heard about this chemical reaction, I think it does not exist.

c) A combustion reaction is when an organic molecule reacts with oxygen to form carbon dioxide and water.

d) A decomposition reaction is when one reactant splits to form two or more products.

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A sample of monochloro pentaborane (9), b5h8cl, has a mass of 20.1 g. what amount, in moles, does this mass represent?
dolphi86 [110]

The number of moles in monochloro pentaborane (9) B_5H_8Cl is 0.37056.

We know that ,

Number of moles =   Given mass/ Molar mass

Given mass of monochloro pentaborane (9) is 20.1 g

The molar mass of monochloro pentaborane (9) is

                                        =  5*B +  8*H + Cl

                                        =  5* 10.811 + 8 * 1 + 35.453

                                        = 54.241

Thus number of moles =  20.1/54.241

                                      = 0.37056

To know more about mole concept

brainly.com/question/20483253

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5 0
1 year ago
[03.04]When one atom of potassium (K) combines with one atom of fluorine (F), an ionic bond forms, resulting in potassium fluori
dybincka [34]
Heyo, I believe that the answer would be D. The valence electrons are given up by the K and gained by the F.
3 0
3 years ago
Express 14.80 × 12.10 × 5.05 in scientific notation with the proper significant figures.
Naya [18.7K]
9.04354 * 10^2

The “*” identifies as a multiplication sign. Hope this helps
8 0
3 years ago
Which iron pot has the least thermal energy?
Yuki888 [10]

Answer:

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Explanation:

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Sonja [21]

Answer:

NH4CL is the answer

Explanation:

Hope it helps you

3 0
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