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GuDViN [60]
2 years ago
8

A student mixes a solution of lead (II) nitrate with a solution of potassium iodide and notices the formation of a yellow solid.

What is the precipitate? How do you know?
Chemistry
1 answer:
ioda2 years ago
5 0

Answer:

Lead (II) iodide

Explanation:

The reaction of lead (II) nitrate, Pb(NO₃)₂ with KI is:

Pb(NO₃)₂(aq) + 2KI(aq) → KNO₃(aq) + PbI₂(s)

This is a typical double-replacement reaction where anions and cations exchange its couple.

All nitrates are solubles, thus, KNO₃ is not the precipitate.

The only possibility of precipitate is PbI₂,

Lead (II) iodide, a yellow and insoluble solid...

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According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the
leva [86]

Answer:

A) carbon  - 2

B) cobalt  - 3

C) sulfur   - 2

D) fluorine   - 1

E) titanium   - 2

F) germanium  - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.  

(A) Carbon.

The electronic configuration is -  

1s^22s^22p^2

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(B) Cobalt.

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{7}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -  

1s^22s^22p^63s^23p^4

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

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1s^22s^22p^5

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{2}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^2

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

4 0
3 years ago
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Levart [38]

Answer:

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Q=mc\Delta T

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m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg

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3 years ago
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