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GuDViN [60]
3 years ago
8

A student mixes a solution of lead (II) nitrate with a solution of potassium iodide and notices the formation of a yellow solid.

What is the precipitate? How do you know?
Chemistry
1 answer:
ioda3 years ago
5 0

Answer:

Lead (II) iodide

Explanation:

The reaction of lead (II) nitrate, Pb(NO₃)₂ with KI is:

Pb(NO₃)₂(aq) + 2KI(aq) → KNO₃(aq) + PbI₂(s)

This is a typical double-replacement reaction where anions and cations exchange its couple.

All nitrates are solubles, thus, KNO₃ is not the precipitate.

The only possibility of precipitate is PbI₂,

Lead (II) iodide, a yellow and insoluble solid...

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Main Answer:

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Explanation:

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valentinak56 [21]

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<h3>Further explanation</h3>

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\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

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