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Ber [7]
2 years ago
6

Answering just one is fine. Please help. It's due in less than an hour

Chemistry
2 answers:
Ber [7]2 years ago
7 0

Answer:

Q 3: the answer is c, W

hope this helps

Dmitriy789 [7]2 years ago
5 0
Q 3: C ( sorry for only one)
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What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
pshichka [43]

Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

Combustion of Methane:

1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

8 0
2 years ago
WS Percent yield don’t understand how to do would appreciate the help
Grace [21]

Answer:

1. Theoretical yield of NaOH is 22.72 g

2. Percentage yield of NaOH = 22.14%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NaHCO₃ —> NaOH + CO₂

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 1 mole (i.e 40 g) of NaOH and 1 mole (i.e 44.01 g) of CO₂.

Next, we shall determine the number of mole of NaHCO₃ that will decompose to produce 25 g of CO₂. This can be obtained as follow:

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 44.01 g of CO₂.

Therefore, Xmol of NaHCO₃ will decompose to 25 g of CO₂ i.e

Xmol of NaHCO₃ = 25 / 44.01

Xmol of NaHCO₃ = 0.568 mole

1. Determination of the theoretical yield of NaOH.

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 40 g of NaOH.

Therefore, 0.568 mole of NaHCO₃ will decompose to produce = 0.568 × 40 = 22.72 g of NaOH.

Thus, the theoretical yield of NaOH is 22.72 g

2. Determination of the percentage yield of NaOH.

Theoretical yield of NaOH = 22.72 g

Actual yield of NaOH = 5.03 g

Percentage yield of NaOH =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 5.03 / 22.72 × 100

Percentage yield of NaOH = 22.14%

4 0
2 years ago
Critical Thinking Challenge: A student has a part time
mina [271]

Answer:

6⅔ shifts

Explanation:

From the question given:

A shift = 4 hours

Pay = $8.25 per hour

Next, we shall determine the number of hours that will result in a pay of $220. This can be obtained as follow:

$8.25 = 1 hour

Therefore,

$220 = $220 × 1 hour / $8.25

$220 = 220/8.25 hours.

$220 = 80/3 hours

$220 = 26⅔ hours

Therefore, it will take 26⅔ hours to receive a pay of $220.

Finally, we shall determine the number of shifts in 26⅔ hours. This can be obtained as follow:

4 hours = 1 shift

Therefore,

26⅔ hours = 26⅔ ÷ 4

26⅔ hours = 80/3 × 1/4

26⅔ hours = 80/12

26⅔ hours = 20/3

26⅔ hours = 6⅔ shifts

Therefore, she will work 6⅔ shifts in order to receive a pay of $220

6 0
3 years ago
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The pressure increase does not affect the equilibrium shift reaction.
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