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NNADVOKAT [17]
4 years ago
10

How do you solve this? It's dealing with three-dimensional figures.

Mathematics
1 answer:
mezya [45]4 years ago
6 0
Imagine you're looking from the views given. If not, look for similar objects in your home and you'll have your reference from there
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Which of the following equations is equivalent to 3/4a-6=1/4
GaryK [48]

Answer:

x=25 over 3

Step-by-step explanation:

3÷4a-6=1÷4 convert to

3

_x-6= 0.25

4

3x-24=1

3x=24+1

3x=25

divide both sides by 3 and you'll get:

25

----

3

5 0
3 years ago
The options are <,>,=
mixer [17]

Answer:

<

Step-by-step explanation:

3 0
4 years ago
Describe each step taken to solve the equation. Then, check the solution to see if it is valid. If it is not a valid solution, e
TEA [102]

Answer:

Step-by-step explanation:

given,

a) √x + 6 = 4                                                    

to solve the above equation subtract both side with 6

    √x + 6 - 6  = 4 - 6                  

                √x  = -2                  

squaring both side

                (√x)² = (-2)²              

                       x = 4            

a) ∛x + 6 = 4                                            

to solve the above equation subtract both side with 6

    ∛x + 6 - 6  = 4 - 6

                ∛x  = -2

cubing  both side

                (√x)³ = (-2)³

                      x = -8

4 0
4 years ago
Find the area and perimeter of the triangle below. Show all work.
Gnoma [55]

Answer:

Area = 20.52 cm^2 and Perimeter = 28.68 cm.

Step-by-step explanation:

Use Pythagoras theorem to find the base of the triangle.

a^2 = 6^2 - 3^2 =  27

a = sqrt27

b^2 = 9^2 - 3^2 =  72

b = sqrt72

Base = sqrt27 + sqrt72

= 13.68

So Area = 0.5 * 13.68 * 3

= 20.52 cm^2   (answer)


Perimeter = 9 + 6 + 13.68

= 28.68  ( answer).

8 0
3 years ago
What is the standard form of the equation of the circle x2 -4x + y2 + 6y + 12 = 0?
Rashid [163]
We take the equation
                            <span>x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
                             </span><span>x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0</span>
<span>                                            (x-2)^2 - 4 + (y+3)^2 - 9 = -12</span>
<span>                                                       <span>(x-2)^2+ (y+3)^2  = 1
Therefore the answer is </span></span><span>(x-2)^2+ (y+3)^2  = 1</span>
4 0
3 years ago
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