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Ber [7]
3 years ago
11

what is the factored form of a fourth degree polynomial function with coefficients that has -3,1and 1+5i

Mathematics
1 answer:
Leokris [45]3 years ago
4 0
Complex factors are
  (x +3)(x -1)(x -1 -5i)(x -1 +5i)

If you want the complex factors combined to a real factor, the factorization is
  (x +3)(x -1)(x² -2x +26)
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ASAP!! ILL GIVE BRAINLEST
densk [106]

Answer:

A^-1:B^-1

Step-by-step explanation:

im not 100% sure but i think this is the right answer :)

8 0
3 years ago
Is X-1 a factor of x^5-1?
Musya8 [376]

Answer: No

Explanation:

According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.

As x-1 is a factor

We equate x-1=0

x=1

Substituting in x^5-1, we have 1^5-1 =1-1=0.

Hence, it's a factor.

When coming to x^5+1, it would become 1^5+1=1+1=2

So x-1 isn't a factor of x^5+1.

4 0
2 years ago
A rectangle with length n and height m. A right triangle with hypotenuse n + 1, length n, and height m.
Oksana_A [137]

9514 1404 393

Answer:

  C. 12cm

Step-by-step explanation:

The equation for the perimeter of the rectangle is ...

  P = 2(L+W)

  34 = 2(n +m)

Solving for m, we get

  m = 17 -n . . . . . . . divide by 2, subtract n

__

The Pythagorean theorem gives the relationship between the sides and the hypotenuse

  m^2 +n^2 = (n+1)^2

  (17 -n)^2 +n^2 = (n +1)^2 . . . . . . substitute for m

  289 -34n +n^2 +n^2 = n^2 +2n +1 . . . . eliminate parentheses

  n^2 -36n +288 = 0 . . . . . . . put in standard form

  (n -12)(n -24) = 0 . . . . . . . . . factor

  n = 12 . . . . . . . . . . n=24 is an extraneous solution here

The value of n is 12 cm.

8 0
3 years ago
What is negative 1/4 to the 3rd power
Y_Kistochka [10]

Answer:

-1/64

Step-by-step explanation:

Just do 4 to the 3rd and make that the denominator

4^3 = 64

-1 / 64

7 0
3 years ago
Read 2 more answers
If a student was randomly guessing while completing a 20 question multiple choice exam, what is the probability they would score
mario62 [17]

Answer:

you want 4 correct and 16 incorrect

there are 20 questions

each question has four answers, so

P(right answer) = 1/4

P(wrong answer) = 3/4

----

Since you want 4 correct of 20 we have a combination of 20C4

This is a binomial problem where p = 1/4, q = 3/4 and we get

(20 "choose" 4)*(probability correct)^(number correct)*(probability incorrect)^(number incorrect)

putting numbers in we get

(20c4)*(1/4)^4*(3/4)^16

This gives us

~ .189685

Step-by-step explanation:

7 0
3 years ago
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