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pychu [463]
3 years ago
9

I need some help with this math question

Mathematics
1 answer:
kherson [118]3 years ago
6 0
Second one :) shshdjehwjsjdjdjs
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Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide
pantera1 [17]

The total flowers is 4 + 3 + 4 = 11

4 roses + 3 carnations = 7

Probability of picking either a rose or a carnation = 7/11

4 0
3 years ago
One large box of birdseed can feed half a dozen parrots for 15 days. For how many days can this same large box of birdseed feed
iren [92.7K]
Box = b
Parrots = p
b/p = number of days it can support the parrots
Half a dozen = 6 (A dozen is 12)
1/6 = 15
To work out the percentage of '6' '5' is, use the equation
(5/6)*100 = 83.333....
Meaning that with one less bird, the box will support the birds for 16.666... (100 - 18.333...) longer
(15/100)*116.666... = 17.4999....
The box will sustain the parrots for 17.5 days
7 0
3 years ago
1) how many significant digits are there in the sum of 45.10 and 102.203?
Sergio039 [100]
Oi  :)

1) There are 3 significant digits
45.10+102.203= 147.303

2)
15 Mi/h  =  22 ft/s

3)
C= 72*m* \frac{3}{4} \\  \\ C= 72*81* \frac{3}{4} \\  \\ C= \frac{17496}{4}  \\  \\ C=4374

4)
There are 4 significant digitis. Leter C 
7 0
3 years ago
A river discharges 4 × 106 cubic feet of water into the Pacific Ocean each second. There are 86,400 seconds in one day. To find
erik [133]

Answer:

3.456E + 14= 3.456X10^{14

Step-by-step explanation:

The river discharges 4X10^6 cubic feet of water into the Pacific Ocean each second.

There are 86,400 seconds in one day.

Amount of water discharges each day

=4X10^6X86400\\=345600000000\\=3.456X10^{11

Since this differs from what you have, I will explain the scientific notation.

3.456E + 14 simply means 3.456X10^{14

The options are not well laid out but you can pick the appropriate option.

8 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools, how many divisions are possible? how many if each school must rece
DaniilM [7]
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then 

( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165

For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
8 0
3 years ago
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