$\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}$

$=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}$

5 0

3 years ago

Read 2 more answers

Whoever helps me will be lucky for the rest of your life

Anvisha [2.4K]

Answer:

A) 3.5

16 shovels full

Step-by-step explanation:

9x + 13 = 17x - 15

8x = 28

x = 3.5

20 + 5x = 32 + 4.25x

0.75x = 12

x = 16

7 0

3 years ago