Our triangle is ABC with ∠C = 90°
1) AB² = BC² + AC² (Pythagorean theorem)
25² = 20² + AC²
AC² = 625 - 400
AC² = 225
AC = 15
2) PΔABC = AB + BC + AC = 25 + 15 + 20 = 60
3) SΔABC = AC * BC * 1/2 = 15 * 20 * 1/2 = 150
Answer: the perimeter is 60 cm and the area is 150 cm² .
The measure of angle C (m ∠C) is 40°
<h3>Calculating angles in a triangle </h3>
From the question, we are to determine the measure of angle C (m ∠C)
In any given triangle, the sum of all the angles is 180°
Thus,
In ΔABC, the angles sum up to 180°
That is,
∠A + ∠B + ∠C = 180°
From the given information,
m ∠A = 80°, m ∠B = 60°
Thus,
80° + 60° + m ∠C = 180°
140° + m ∠C = 180°
m ∠C = 180° - 140°
m ∠C = 40°
Hence, the measure of angle C (m ∠C) is 40°
Learn more on Calculating angles in a triangle here: brainly.com/question/17738179
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The common denomenators of the denomenaotrs is 6(x+1)
times both the fraction by (6(x+1))/(6(x+1))
we get
(5(6)(x+1))/((x+1)+6)=(30(x+1))/(x+7)=(30x+30)/(x+7)
Answer:
Step-by-step explanation:
Change in y over the change in x
