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stepan [7]
2 years ago
14

Find the inverse of g(x) = 2x^3 +3 Step by step working please I want to learn

Mathematics
2 answers:
Zepler [3.9K]2 years ago
8 0

g(x)=2x^3+3\to y=2x^3+3

replace x with y

2y^3+3=x\ \ \ |-3\\\\2y^3=x-3\ \ \ |:2\\\\y^3=\dfrac{x-3}{2}\to y=\sqrt[3]{\dfrac{x-3}{2}}

Answer: g^{-1}(x)=\sqrt[3]{\dfrac{x-3}{2}}

malfutka [58]2 years ago
3 0

Set g(x) as y. Then you get y = 2x^3 + 3. Switch Y with X and you get x = 2y^3 + 3. Now you can put everything with x getting, y = cuberoot[(x-3)/2]

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