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3 years ago

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Find the inverse of g(x) = 2x^3 +3 Step by step working please I want to learn

2 answers:

Zepler [3.9K]3 years ago

8 0

$g(x)=2x^3+3\to y=2x^3+3$

replace x with y

$2y^3+3=x\ \ \ |-3\\\\2y^3=x-3\ \ \ |:2\\\\y^3=\dfrac{x-3}{2}\to y=\sqrt[3]{\dfrac{x-3}{2}}$

Answer: $g^{-1}(x)=\sqrt[3]{\dfrac{x-3}{2}}$

malfutka [58]3 years ago

3 0

Set g(x) as y. Then you get y = 2x^3 + 3. Switch Y with X and you get x = 2y^3 + 3. Now you can put everything with x getting, y = cuberoot[(x-3)/2]

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Solve 5x 2 - 7x + 2 = 0 by completing the square. What are the solutions?

Alexeev081 [22]

Answer:

$x=\frac{2}{5}$ or $x=1$

Step-by-step explanation:

The given quadratic equation is

$5x^2-7x+2=0$

Group the constant terms on the right hand side.

$5x^2-7x=0-2$

$5x^2-7x=-2$

Divide through by 5.

$x^2-\frac{7}{5}x=-\frac{2}{5}$

Add the square of half the coefficient of x., which is $(\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100}$ to both sides of the equation.

$x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}$

The left hand side is now a perfect square.

$(x-\frac{7}{10})^2=\frac{9}{100}$

Take the square root of both sides;

$(x-\frac{7}{10})=\pm \sqrt{\frac{9}{100}}$

$x-\frac{7}{10}=\pm \frac{3}{10}$

$x=\frac{7}{10}\pm \frac{3}{10}$

$x=\frac{7-3}{10}$ or $x=\frac{7+3}{10}$

$x=\frac{4}{10}$ or $x=\frac{10}{10}$

$x=1$ or $x=\frac{2}{5}$

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Step-by-step explanation:

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Using the segment addition postulate, which is true? What is the measure of AngleDCF? Three lines extend from point C. The space

Flura [38]

Answer:

129

Step-by-step explanation:

If three lines CD, CE and CF extend from point C, then the following addition postulate is true;

<DCE + <ECF = <DCF

If the space between line C D and C E is 75 degrees, then <DCE = 75

If the space between lines C E and C F is 54, then <ECF = 54.

Substitute the given values into the expression above will give;

<DCF =<DCE + <ECF

<DCF = 75+54

<DCF = 129

Hence the measure of <DCF is 129°

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3 years ago

What is the value of x? <br>A.39<br>B.41<br>C.26<br>D.17

mojhsa [17]

Answer:

The answer is B.

Step-by-step explanation:

You have to use Pythogorean Theorem, c² = a² + b² where c is the hypotenuse and a,b is the side lengths :

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$c = 41 \: units$

*Take note, hypotenuse will <u>a</u><u>l</u><u>w</u><u>a</u><u>y</u><u>s</u><u> </u><u>b</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>l</u><u>o</u><u>n</u><u>g</u><u>e</u><u>s</u><u>t</u><u> </u><u>l</u><u>e</u><u>n</u><u>g</u><u>t</u><u>h</u> among the 3 lengths.

*Pythogorean Theorem can only applied in a right-angle triangle.

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