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3 years ago

Find the number of degrees in the third angle of the triangle.

Mathematics

2 answers:

ddd [48]3 years ago

7 0

The missing angle is 31 degrees.

You can know this because the sum of the measures of a triangle is always 180.

All you have to do is add up the known measure of the triangle and subract that from 180

Svet_ta [14]3 years ago

7 0

The answer for X is 31

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Justin started eating lunch at 12:23 and finish at 12:45. How many elapse time while he was eating lunch

lyudmila [28]

Answer:

the answer is 22 minutes

Step-by-step explanation:

because when you need to add 2 to get 12:25 and then u add 20 more minutes which then gives takes u to 12:45 then add the time u added and that is the answer, 22 minutes

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2 years ago

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Joann has decided to purchase a new car. What should she do next according to the decision-making process?

Luda [366]

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3 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

3 0

2 years ago

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Ippppppppppppppppppopkokhiufytedfliyhuigjboihlk.h

Lemur [1.5K]

Answer:

it b

Step-by-step explanation:

5 0

2 years ago

HELP ME PLEASE I NEED HELP

Olin [163]

Step-by-step explanation:

You should prolly subtract 2 from both sides first.

So you get, -|2/5x + 3| > -1 2/5

Add three to both sides
-|2/5x| = -1 2/5
Do -1 and 2/5 divided by 2/5 to get -3.5, x > -3.5

One of the answers is x > -3.5 but you need to switch the sign to less than and make the other side the opposite.

$-( \frac{2}{5}x + 3 ) < 1 \frac{2}{5}$

You see that, switched the sign and made whats on the right side opposite. So now solve for x again but with this new equation. Also, the parentheses are absolute value signs

Subtract 3 from both sides

-|2/5x| < -1 and 3/5

Divide 2/5 from each side to get x < -4

I hope I'm correct, my bad if I'm wrong

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2 years ago

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