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3 years ago

An office remodeling project costs $15,880. If you pay $3,680

Mathematics

1 answer:

elena-s [515]3 years ago

5 0

Answer:

23.17%

Step-by-step explanation:

The project costs $15,880 of which you contributed $3,680. To know the percentage of how much you finance,

(amount paid / cost)*100%

= (3680/15880)*100%

= (0.231738035)*100%

= 23.1738035%

Thus the amount contributed is 23.17% of the cost.

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nolan uses 7 inches of string to make each bracelet. if nolan makes 3 bracelets, how many inches of string will he use?

pantera1 [17]

Answer:

21 inches

Step-by-step explanation:

We can write a ratio to solve

7 inches x inches

------------- = -------------------

1 bracelet 3 bracelets

Using cross products

7*3 = 1x

21 = x

21 inches

6 0

2 years ago

Read 2 more answers

How do I find x and y using what is in the equation

Tatiana [17]

y is part of a right angle on line AB

a right angle = 90 degrees

90-47 = 43 degrees

y = 43 degrees

a straight line = 180 degrees

180-47 = 133 degrees

x = 133 degrees

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3 years ago

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FrozenT [24]

Answer:

What grade is this?

Step-by-step explanation:

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3 years ago

There are 52 weeks in a year. Ben has lived in london for two fifths of year. How many weeks has ben lived in london?

masha68 [24]

Answer:

$\frac{104}{5}$ weeks or $20\frac{4}{5}$ weeks

Step-by-step explanation:

To do this we can set up a proportion

$\frac{52}{1} *\frac{2}{5}$

This will tell us how many weeks are in 2/5 of a year

Let's evaluate this

$\frac{104}{5}$

We cannot simplifiy this anymore, so we will leave it as an improper fraction, or a mixed number as shown below

$20\frac{4}{5}$ weeks

5 0

3 years ago

Read 2 more answers

When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic

Elanso [62]

Answer:

95% Confidence interval for the mean

$142.8 \leq\mu\leq158.4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

$cf=\sqrt{\frac{N-n}{N-1} }$

The standard deviation can be estimated as

$\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963$

The 95% confidence interval has a z value of 1.96, so it becomes:

$M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4$

5 0

3 years ago