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3 years ago

Sharon spends 24 hours on her tablet each week. How many hours does she

Mathematics

2 answers:

melisa1 [442]3 years ago

5 0

Sharon spends 1248 because there are 52 weeks in a year and 24 * 52 = 1248

mamaluj [8]3 years ago

4 0

Answer:

She spends 1,248 hours on her tablet.

Step-by-step explanation:

24 hours each week is given. Since there are 52 weeks in 1 year multiply 52 x 24= 1,248

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Find the exact values of the six trigonometric functions of the given angle. If any are not defined, say "not defined." Do not u

Solnce55 [7]

Answer:

Step-by-step explanation:

Let's take a look at the given angle 135°

The sketch of the angle which corresponds to $-\dfrac{3\pi}{4}$ unit circle and can be seen in the attached image below;

The trigonometric ratios are as follows for an angle θ on the unit circle:

Trigonometric ratio related ratio on coordinate axes

sin θ $\dfrac{y}{1}$

cos θ $\dfrac{x}{1}$

tan θ $\dfrac{y}{x}$

csc θ $\dfrac{1}{y}$

sec θ $\dfrac{1}{x}$

cot θ $\dfrac{x}{y}$

From the sketch of the image attached below;

The six trigonometric ratio for 135° can be expressed as follows:

$sin (-\dfrac{3\pi}{4})= \dfrac{y}{1}$

$sin (-\dfrac{3\pi}{4})=- \dfrac{\sqrt{2}}{2}$

$cos (-\dfrac{3\pi}{4})= \dfrac{x}{1}$

$cos (-\dfrac{3\pi}{4})= -\dfrac{\sqrt{2}}{2}$

$tan (-\dfrac{3\pi}{4})= \dfrac{y}{x}$

$tan (-\dfrac{3\pi}{4})= \dfrac{-\dfrac{\sqrt{2}}{2}}{-\dfrac{\sqrt{2}}{2}}$

$tan (-\dfrac{3\pi}{4})= -\dfrac{\sqrt{2}}{2}} \times {-\dfrac{2}{\sqrt{2}}$

$tan (-\dfrac{3\pi}{4})= 1$

$csc (-\dfrac{3\pi}{4})= \dfrac{1}{y} \\ \\ csc (-\dfrac{3\pi}{4})=\dfrac{1}{-\dfrac{\sqrt{2}}{2}} \\ \\ csc=1 \times -\dfrac{2}{\sqrt{2}} \\ \\csc =-\sqrt{2}$

$sec (-\dfrac{3 \pi}{4})=\dfrac{1}{x} \\ \\ sec = \dfrac{1}{(-\dfrac{\sqrt{2}}{2})} \\ \\ sec = 1 \times -\dfrac{2}{\sqrt{2}} \\ \\ sec = - \sqrt{2}$

$cot(-\dfrac{3 \pi}{4}) = \dfrac{x}{y} \\ \\ cot(-\dfrac{3 \pi}{4}) = \dfrac{-\dfrac{\sqrt{2}}{2} }{-\dfrac{\sqrt{2}}{2}} \\ \\ cot(-\dfrac{3 \pi}{4})= -\dfrac{\sqrt{2}}{2} } \times {-\dfrac{2}{\sqrt{2}}} \\ \\ cot (-\dfrac{3 \pi}{4}) = 1$

4 0

3 years ago

Find the number that belongs in the green box. Round your answer to the nearest tenth

Umnica [9.8K]

Answer:

134.5 degree

Step-by-step explanation:

first find the remaining side of a triangle

BY using cosine rule

C^2=A^2+B^2-2ABcosx

apply square root both sides

√c^2 =√[4^2+10^2-2(4)(10)cos29]

C=√(116-69.96958)

C=√46.03

C=6.8

Now find angle using cosine rule

C^2=A^2+B^2-2ABcosx

10^2=4^2+6.78^2-2(4)(6.78)cosx

100=16+45.9684-54.24cosx

100=61.9684-54.24cosx

100-61.9684=-54.24cosx

(38.0316)/-54.24=(-54.4cosx)/-54.24

-0.70117=cosx

X= cos inverse of -0.70117

x=134.5 degree

5 0

2 years ago

Read 2 more answers

Find the volume for the regular pyramid. V =

kakasveta [241]

Answer:

$Volume=\frac{16\sqrt{2} }{3}units^{3}$

Step-by-step explanation:

∵ The volume of the pyramid = 1/3 base area × height

∵ The base is equilateral Δ with side length 4

∴ The area of the bast = 1/4 × 4² × √3 = 4√3 units²

To get the height of the pyramid draw it from the vertex of the top of the pyramid ⊥ to the base on the centro-id of the base which divides the height of the triangle two ratio 2:1 from the vertex of the triangle

∵ The height of the base = √(4² - 2²) =√12 = 2√3

∴ 2/3 the height = 4√3/3 ⇒ (2:1 means 2/3 from the height)

∴ The height of the pyramid = √[4² - (4√3/3)²] = √[16 - 48/9]

∴ h = 4√2/√3 (4√6/3 in its simplest form)

∴ V = 1/3 × 4√3 × 4√2/√3 = 16√2/3 units³

∴ $V = \frac{16\sqrt{2} }{3}$

6 0

3 years ago

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Laws Of Indicies Can someone please help me with this?

nasty-shy [4]

Answer:

See below

Step-by-step explanation:

$1) : {a}^{5} {b}^{4} {c}^{3} \div {a}^{2} {b}^{3} c \\ \\ = {a}^{5 - 2} {b}^{4 - 3} {c}^{3 - 1} \\ \\ = {a}^{3} {b}^{1} {c}^{2} \\ \\ = {a}^{3} {b} {c}^{2} \\ \\ \\2)\: (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4} \div ( {a}^{2} \times 3a) \\ \\ = 5 {a}^{4} \div (3 {a}^{2 + 1} ) \\ \\ = 5 {a}^{4} \div (3 {a}^{3} ) \\ \\ = \frac{5}{3} {a}^{4 - 3} \\ \\ = \frac{5}{3} {a} \\ \\ \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4} } \\ \\ = \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} } \\ \\ = \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} } \\ \\ = \frac{ {a}^{5} }{ {a}^{7} } \\ \\ = {a}^{5 - 7} \\ \\ = {a}^{ - 2} \\ \\ = \frac{1}{{a}^{2} } \\ \\$

8 0

3 years ago

Read 2 more answers

Plz help me! It’s math!

serious [3.7K]

Answer:

The first one

Step-by-step explanation:

The number line is supposed to show the product of 2 and five, the arrow will start at 0 because 5 times 0 is 0 then it will go to 5 because 5 times 1 is 5, then another arrow will start at 5 and point at 10 because 5 times 2 is 10

The second option points backwards which would be if you were dividing 10 by 5

The third option starts at negative 10 so it shows -10 divided by -5

the last option starts at 0 and goes to -10 so it shows -5 multiplied by 2

7 0

3 years ago

Read 2 more answers