Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
Answer:
4
Step-by-step explanation:
my theory would be 4
Yes you would be correct!
Garnetta will have 3,200 shares worth $ 34,125 each.
Given that Garnetta owned 2400 shares of Metropolitan Corporation at a price of $ 45.50, and the stock split 4-for-3, to determine how Garnetta was financially affected by the split the following calculation must be performed:
- 3 = 2400
- 4 = X
- 4 x 2400/3 = X
- 9600/3 = X
- 3200 = X
- (2400 x 45.50) / 3200 = X
- 109200/3200 = X
- 34.125 = X
Therefore, Garnetta will have 3,200 shares worth $ 34,125 each.
Learn more in brainly.com/question/13981349
Example 250
word form:
two hundred and fifty
expanded form:
2+5+0
standard form:
250