A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft. Projectile motion formula h(t) = -16t2 + vt + h0 h0 = 6.5 v = ? h = 5 when t = 3.5 Determine the value of v, rounded to the nearest whole number.
2 answers:
Answer: v= 56 ft per second
Step-by-step explanation:
Given: A quarterback throws a football to a teammate.
Projectile motion formula is given by :-
, where
Now, to find v at h=5 and t=3.5, substitute these values in the above equations, we get
Answer:
The value of v, rounded to the nearest whole number = 56 ft/s
Step-by-step explanation:
The equation of Projectile motion formula is
h(t) = -16t² + vt + h₀
We have h₀ = 6.5
Substituting
h(t) = -16t² + vt + 6.5
h = 5 when t = 3.5, that is h(3.5) = 5
Substituting
h(3.5) = -16 x 3.5² + v x 3.5 + 6.5 = 5
3.5v = 194.5
v = 55.57 ft/s = 56 ft/s
The value of v, rounded to the nearest whole number = 56 ft/s
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