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laila [671]
3 years ago
11

The scatter plot below shows the first ionization energies and atomic radii of several of the second- and third-period elements

of the periodic table: N at (1400,0.75); O at (1300,0.6); C at (1200,0.90); S at (1000,1.1); P at (1100,1.2); B at (800,1.2); Be at (900,1.4); Si at (750,1.5), Mg at (700,1.6); Al at (590,1.7); Li at (500,2.0); Na at (450,2.3); K at (410,2.7) Which conclusion can be drawn based on the information in this graph? As the electronegativity value for the elements increases, the atomic radius decreases. The electronegativity values and the atomic radii of these elements are directly proportional. As the electronegativity value of the elements increases, the atomic radius increases exponentially. No relationship appears to exist between the atomic radius and the first ionization energy of an element.
Chemistry
2 answers:
aksik [14]3 years ago
6 0
D.) <span>No relationship appears to exist between the atomic radius and the first ionization energy of an element.

Hope this helps!</span>
drek231 [11]3 years ago
5 0
No relationship appears to exist between the atomic radius and the first ionization energy of an element.
I am not so sure cause I am not so go at chemistry
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Answer:

  • <u><em>The first statement is false:  a.At equilibrium, equal amounts of products and reactants are present. ΔG° is a function of Keq.</em></u>

Explanation:

When one part of a statement is false, the whole statement is false.

At <em>equilibrium,</em> the amounts of products and reactants does not have to be equal.

At equlibrium the rates of the forward reaction and the reverse reaction must be equal.

An equilibrium reaction may be represented by:

  • A + B ⇄ C + D

That represents two reactions:

  • Direct reaction: A + B → C + D (A and B yield C and D)

  • Reverse reaction: A + B ← C + D (C and D yield A and B: note that the arrow goes from right to left)

So, it is when the direct and the forward rates are equal that there is not net change in the amounts of all the species and so the reaction is is equilibrium).

As per the other statement, both parts are true:

  • When reactants become products, they do so through an intermediate transitrion state: when the reactants approach each other and collide with enough energy and appropiate position, the bonds start to break and the bonds of the products start to form. This is the transition state.

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5 0
3 years ago
How much energy is required to move the electron of the hydrogen atom from the 1s to the 2s orbital?
Alja [10]

Answer:

1.63425 × 10^- 18 Joules.

Explanation:

We are able to solve this kind of problem, all thanks to Bohr's Model atom. With the model we can calculate the energy required to move the electron of the hydrogen atom from the 1s to the 2s orbital.

We will be using the formula in the equation (1) below;

Energy, E(n) = - Z^2 × R(H) × [1/n^2]. -------------------------------------------------(1).

Where R(H) is the Rydberg's constant having a value of 2.179 × 10^-18 Joules and Z is the atomic number= 1 for hydrogen.

Since the Electrons moved in the hydrogen atom from the 1s to the 2s orbital,then we have;

∆E= - R(H) × [1/nf^2 - 1/ni^2 ].

Where nf = 2 = final level= higher orbital, ni= initial level= lower orbital.

Therefore, ∆E= - 2.179 × 10^-18 Joules× [ 1/2^2 - 1/1^2].

= -2.179 × 10^-18 Joules × (0.25 - 1).

= - 2.179 × 10^-18 × (- 0.75).

= 1.63425 × 10^- 18 Joules.

7 0
3 years ago
What does the Kinetic Theory of Matter state that matter is composed of?
Ahat [919]
 <span>Theory of Matter state that matter is composed of?
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What is chemical formula for: Iron (III) fluoride
True [87]

Answer:

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Explanation:

You have to break this problems down and know the naming rules.

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- Add together - FeF

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- FeF3

- Hope that helps! Please let me know if you need further explanation.

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