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laila [671]
3 years ago
11

The scatter plot below shows the first ionization energies and atomic radii of several of the second- and third-period elements

of the periodic table: N at (1400,0.75); O at (1300,0.6); C at (1200,0.90); S at (1000,1.1); P at (1100,1.2); B at (800,1.2); Be at (900,1.4); Si at (750,1.5), Mg at (700,1.6); Al at (590,1.7); Li at (500,2.0); Na at (450,2.3); K at (410,2.7) Which conclusion can be drawn based on the information in this graph? As the electronegativity value for the elements increases, the atomic radius decreases. The electronegativity values and the atomic radii of these elements are directly proportional. As the electronegativity value of the elements increases, the atomic radius increases exponentially. No relationship appears to exist between the atomic radius and the first ionization energy of an element.
Chemistry
2 answers:
aksik [14]3 years ago
6 0
D.) <span>No relationship appears to exist between the atomic radius and the first ionization energy of an element.

Hope this helps!</span>
drek231 [11]3 years ago
5 0
No relationship appears to exist between the atomic radius and the first ionization energy of an element.
I am not so sure cause I am not so go at chemistry
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Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338
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\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M

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