4 years ago

When copper (I) oxide dissolves in dilute sulfuric acid, copper (II) sulfate and copper are produced

Chemistry

1 answer:

const2013 [10]4 years ago

7 0

Answer:

Cu2O + H2SO4 ——> CuSO4 + Cu + H2O

Cu2O is oxidized and reduced. It lost an electron in CuSO4 for the 2+ charge, but it gained an electron in Cu to go from the 1+ charge to a neutral charge. This is dismutation (aka disproportionation)

Explanation:

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balu736 [363]

Hello!

The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.

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$P_n*V_n=n*R*T_n \\ \\ n*R= \frac{P_n*V_n}{T_n}$

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Have a nice day!

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