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julsineya [31]
4 years ago
12

When copper (I) oxide dissolves in dilute sulfuric acid, copper (II) sulfate and copper are produced

Chemistry
1 answer:
const2013 [10]4 years ago
7 0

Answer:

Cu2O + H2SO4 ——> CuSO4 + Cu + H2O

Cu2O is oxidized and reduced. It lost an electron in CuSO4 for the 2+ charge, but it gained an electron in Cu to go from the 1+ charge to a neutral charge. This is dismutation (aka disproportionation)

Explanation:

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Also, we know, 1 Å = 10^{-10} m

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Learn more about energy of photon -

brainly.com/question/15946945

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