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3 years ago

Where is mechanical energy converted to electrical energy?

Chemistry

2 answers:

nata0808 [166]3 years ago

6 0

Answer:

Option C.The mechanical energy generated from the spinning turbine is converted to electrical energy by rotating a wire in a magnetic field.

Explanation:

$have \: a \: great \: dayyyy....$

zysi [14]3 years ago

4 0

Answer:

CORRECT answer is Option (c)

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$\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}$

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Even though we have known of many nuclear energy technologies for about one century some of these technologies have not yet been

Romashka [77]

Answer: The nuclear fission reaction of U-234.043 is written below.

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

$^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{A}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV$

To calculate A:

Total mass on reactant side = total mass on product side

234.043 = 137.159 + A + 3(1.0087)

A = 93.858

Now, the chemical equation becomes:

$^{234.043}_{92}\textrm{U}\rightarrow ^{137.159}_{54}\textrm{Xe}+^{93.858}_{38}\textrm{Sr}+3^{1.0087}_0\textrm{n}+180MeV$

Hence, the nuclear fission reaction of U-234.043 is written above.

7 0

3 years ago

Which element below could be an isotope of beryllium

Cerrena [4.2K]

Answer:

beryllium

Explanation:

isotopes are same elements

7 0

3 years ago

Read 2 more answers

Why iodide ions cannot be determined by Mohr method

pickupchik [31]

Answer:

Exactly the same approach can be used for determination of bromides. Other halides and pseudo halides, like I- and SCN-, behave very similarly in the solution, but their precipitate tends to adsorb chromate anions making end point detection difficult.

Hope it helps!

8 0

3 years ago

If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?

kolezko [41]

Answer:

3.0M

Explanation:

The dilution formula is:

$M_1\times V_1=M_2\times V_2$

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

M₁ = 6.0M

M₂ = unknown

V₁ = 251 mL

V₂ = 500. mL

$6.0M\times 251ml=M_2\times 500.ml$

Clear M₂ and compute:

$M_2=6.0M\times 251ml/500.ml\approx3.0M$

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3 years ago

Help me please I need to know

rjkz [21]

C- Electron
A-Nucleus
B-Neutron
D-Protron

7 0

3 years ago