<span>A light year is equal to
</span>5,866,000,000,000,000!
Sorry
Answer:
d= 14.007 amu
Explanation:
Abundance of N¹⁴ = 99.63%
Abundance of N¹⁵ = 0.37%
Atomic mass of N¹⁴ = 14.003 amu
Atomic mass of N¹⁵ = 15.000 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100
Average atomic mass = 1395.12 + 5.55 / 100
Average atomic mass = 1400.67/ 100
Average atomic mass = 14.007 amu.
Answer:
its the stamen, it also supports the Anther.
Answer:
0.89 moles of N2 gas
Explanation:
From Avogadro's law:
V1/n1 = V2/n2
n2 = V2n1/V1
V1=11.2L
V2= 20L
n1=0.5 moles
n2 = ??
Therefore
n2= 20×0.5/11.2= 0.89 moles
If a material contains three elements joined in a fixed proportion, it is a(an) _____.
d.) compound
