Answer:
Conversion of kinetic energy to potential energy (chemo mechanical energy)
In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy
Conversion of the stored potential energy in the stretched to kinetic energy
By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.
Explanation:
They are not similar at all they are completely different. It even says it in the words
Answer: The rate of appearance of
is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of HBr =
= ![\frac{1d[H_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BH_2%5D%7D%7Bdt%7D)
Rate in terms of appearance of
= ![\frac{1d[Br_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BHBr%5D%7D%7B2dt%7D%3D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
Given :
![-\frac{1d[HBr]}{dt}=0.140Ms^{-1}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BHBr%5D%7D%7Bdt%7D%3D0.140Ms%5E%7B-1%7D)
The rate of appearance of
;
![\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1d%5BHBr%5D%7D%7B2dt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.140%3D0.0700Ms%5E%7B-1%7D)
Thus rate of appearance of
is 
The dichotomous key is not given here, however, the correct dichotomous key is as follows:
step- 1a cell has a nucleus and organelles - go to step 2
1b cell has no nucleus or organelles - bacterial cell
step- 2a cell has a cell wall - go to step 3
2b cell has no cell wall - animal cell
step- 3a cell has chloroplasts - plant cell
3b cell has no chloroplasts - fungal cell
Using this dichotomous key the cell can be identified as - Fungal cell.
A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.
Identification of the given cell:
1. Follow step 1.
- If cells have a nucleus and organelles - yes then go to step 2
2. follow step 2.
- 2a. if cell has a cell wall - yes go to step 3
3. follow step 3.
- 3a. if cell has chloroplasts - no then fungal cell
Fungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.
Thus, Using this dichotomous key the cell can be identified as - Fungal cell.
Learn more about fungal cells:
brainly.com/question/14470940
Answer:
Its nucleus
Explanation:
also contains two neutrons. Since 2 + 2 = 4, we know that the mass number of the helium atom is 4. Finally, the helium atom also contains two electrons since the number of electrons must equal the number of protons.