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igomit [66]
3 years ago
6

Two pieces of pure copper are shown below. The two pieces must have the same ?

Physics
1 answer:
Gnesinka [82]3 years ago
5 0
Visibly you can see that the two copper are different sizes so the mass and volume are different. No information is given about the temperature but they are side by side so you can assume they're both room temp. The density is a ratio of mass per volume. The density will remain the same unless the two are different purities or physical states.
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List these things in order of size, starting with the smallest thing:
jek_recluse [69]
Moon, earth, sun solar system, galaxy, universe
4 0
3 years ago
On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik
RUDIKE [14]
(a)
The velocity of the meteorite just before hitting the ground is:
v=20 km/s=20000 m/s
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
\Delta K =  \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J

(b) 1 megaton of tnt is equal to 1 MT=4.2 \cdot 10^{15}J
To find to how many megatons the meteorite energy loss \Delta E
corresponds, we can set the following proportion
1 MT: 4.2 \cdot 10^{15}J=x: \Delta E
And so we find
x=  \frac{\Delta E}{4.2 \cdot 10^{15}J}  = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of \Delta E=0.162 MT=162 kT. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
1:13 kT=x:162 kT
And so we find
x= \frac{162 kT}{13 kT}=12.46
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
7 0
4 years ago
The force of attraction that a -40.0 μC point charge exerts on a +108 μC point charge has magnitude 4.00 N. How far apart are th
Karolina [17]

Answer:

F = k q1 q2 / r^2

r^2 = k q1 q2 / F  = 9E9 * 4E-5 * 10.8E-5 / 4

r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2

r = 3.12 m

8 0
3 years ago
An electromagnetic wave traveling in a
Phoenix [80]
The answer is (a) 6,000,000m
7 0
4 years ago
The Sun converts 4 × 109 kg of mass to energy every second. How many years would it take the Sun to convert a mass equal to the
natulia [17]

Answer:

4.74 x 10⁷ yr

Explanation:

m = Rate of conversion of mass to energy by sun = 4 x 10⁹ kg/s

t = total time taken to convert mass of earth to energy

M = mass of earth = 5.98 x 10²⁴ kg

Using the equation

M = m t

5.98 x 10²⁴ = (4 x 10⁹) t

t = 1.495 x 10¹⁵ sec

we know that, 1 yr = 3.154 x 10⁷ sec

t = (1.495 x 10¹⁵ sec)  (3.154 x 10⁷ sec)⁻¹ yr

t = 4.74 x 10⁷ yr

3 0
4 years ago
Read 2 more answers
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