Moon, earth, sun solar system, galaxy, universe
(a)
The velocity of the meteorite just before hitting the ground is:

The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:

(b) 1 megaton of tnt is equal to

To find to how many megatons the meteorite energy loss

corresponds, we can set the following proportion

And so we find

So, 0.162 megatons.
(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of

. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:

And so we find

So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
Answer:
F = k q1 q2 / r^2
r^2 = k q1 q2 / F = 9E9 * 4E-5 * 10.8E-5 / 4
r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2
r = 3.12 m
The answer is (a) 6,000,000m
Answer:
4.74 x 10⁷ yr
Explanation:
m = Rate of conversion of mass to energy by sun = 4 x 10⁹ kg/s
t = total time taken to convert mass of earth to energy
M = mass of earth = 5.98 x 10²⁴ kg
Using the equation
M = m t
5.98 x 10²⁴ = (4 x 10⁹) t
t = 1.495 x 10¹⁵ sec
we know that, 1 yr = 3.154 x 10⁷ sec
t = (1.495 x 10¹⁵ sec) (3.154 x 10⁷ sec)⁻¹ yr
t = 4.74 x 10⁷ yr