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Anastaziya [24]
3 years ago
9

You can encrypt individual files, but microsoft recommends encrypting at what level?

Computers and Technology
1 answer:
vichka [17]3 years ago
4 0
Microsoft recommends encrypting at the folder level.
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Suppose you will invest $100 per month at the beginning of the month for 40 years with interest rate
Alexeev081 [22]

Answer:

future value = 232369.1361

return % = 384.10 %

Explanation:

given data

principal = $100 per month

time = 40 year = 480 months

rate = 6.25 % yearly = 0.0625 yearly = 0.005208 monthly

to find out

total amount of capital at the end of your investment and percentage is  your total return

solution

so here future value formula is

future value = P \frac{(1+r)^{t-1}}{r} * (1+r)   ..........1

here r is rate and t is time and P is principal

so put all value

future value = 100 \frac{(1+0.005208)^{480-1}}{0.005208} * (1+0.005208)

future value = 232369.1361

so

Total capital at the end of investment-Total principle invested over the years

232369.1361 - 100 ( 12 × 40 )

184369.1361

so

Return % = \frac{184369.1361}{48000} × 100

return % = 384.10 %

5 0
3 years ago
Exactly how many times must the merge function call each of read and write to merge two arrays of size n/2 into an array of size
Rom4ik [11]

Answer:

Exactly how many times must the merge function call each of read and write to merge two arrays of size n/2 into an array of size n, assuming

i don t know

7 0
3 years ago
When entering data into a cell, which keyboard key is used to remove characters to the left of the insertion point?
deff fn [24]
The backspace key is used for that
3 0
3 years ago
Bruh why is everyone skipping my question!!!!!!!
DiKsa [7]

Answer:

What is your question?

Explanation:

7 0
3 years ago
4. Refer to the following code the answer the remaining questions. loop: load r1, r5, 40 ; r1  data_memory[r5 + 40] add r1, r1,
Anni [7]

Answer:

See explaination

Explanation:

Loop Unrolling

Assembly code

loop:

load r1, r5, 40 //r1 = Mem[r5 + 40]

load r6, r5, 36 //r6 = Mem[r5 + 36]

add r7, r6, r2 //r7 = r6 + r2

store r7, r5, 36 //Mem[r5 + 36] = r7

add r1, r1,r2 //r1 = r1 + r2

store r1, r5, 40 //Mem[r5 + 40] = r1

addi r5, r5, -8 //r5 = r5 -8

bne r5, 0, loop //if(r5 != 0)branch to loop

4 0
4 years ago
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