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Arada [10]
3 years ago
12

Select the proper order from least to greatest for 2⁄3 , 7⁄6 , 1⁄8 , 9⁄10 . A. 1⁄8 , 2⁄3 , 9⁄10 , 7⁄6 . B. 7⁄6 , 9⁄10 , 2⁄3 , 1⁄

8 . C. 2⁄3 , 9⁄10 , 7⁄6 , 1⁄8 . D. 1⁄8 , 9⁄10 , 7⁄6 , 2⁄3 .
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0
The answer to your question is A
drek231 [11]3 years ago
6 0
Let's look at the one that is less than 1/2.
This would be 1/8, so that should go first. We can eliminate B and c.
7/6 is more than 1, so we can eliminate d.
So, A would be the answer.
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We have to calculate by multiplying 5,000 and total number of months
7 0
3 years ago
A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju
weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

V_0 = 12 m/s

\theta = 20^0

g=9.8 m/s^2

At maximum height:

V_y = 0

Components of initial velocity:

V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s

V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s

To find time to reach maximum height:

V_y = V_0y -gt

Plugging in the known values:

0 = 4.10 - 9.8t

t = \frac{-4.10}{-9.8}

t = 0.418 s

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m

8 0
3 years ago
Eliminate the parameter. x = t2 + 2, y = t2 - 4
stepan [7]
\bf \begin{cases}
x=t^2+2\implies x-2=t^2\implies \sqrt{x-2}=\boxed{t}\\\\
y=t^2-4\\
----------\\
y=\left( \boxed{\sqrt{x-2}} \right)^2-4\implies y=x-2-4\\\\
y=x-6
\end{cases}

just a plain vanilla substitution

8 0
3 years ago
Read 2 more answers
X^2+25x-156=0 ayúdenme
Sonbull [250]
X= -25/2 + 1/2 _/1249
3 0
2 years ago
Can someone help me please, thanks.
Natasha2012 [34]
No it won’t work sorry for the concierge room
3 0
3 years ago
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