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Arada [10]
3 years ago
12

Select the proper order from least to greatest for 2⁄3 , 7⁄6 , 1⁄8 , 9⁄10 . A. 1⁄8 , 2⁄3 , 9⁄10 , 7⁄6 . B. 7⁄6 , 9⁄10 , 2⁄3 , 1⁄

8 . C. 2⁄3 , 9⁄10 , 7⁄6 , 1⁄8 . D. 1⁄8 , 9⁄10 , 7⁄6 , 2⁄3 .
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0
The answer to your question is A
drek231 [11]3 years ago
6 0
Let's look at the one that is less than 1/2.
This would be 1/8, so that should go first. We can eliminate B and c.
7/6 is more than 1, so we can eliminate d.
So, A would be the answer.
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1. Simplify: (6-√5)(5+√5)
aniked [119]
150 because 6 times 5 is 30 then you multiply whats inside the square root thing so you'd get 25, 25 is a perfect square which simplifies to 5 then 5 times 30 is 150.
7 0
3 years ago
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Quick I need help 23 and 24 easy seventh grade math
Alekssandra [29.7K]

Answer:-14, -26

Step-by-step explanation:

13-4=9

4-9=-5

From here you can see that the pattern is -9

-5-9=-14

23. is -14

16-2=14

2-14=-12

From here you can see that the pattern is -14

-12-14=-26

24. is -14

6 0
3 years ago
Find the volume h=12cm r=5cm
Goshia [24]

If this was a cone, the volume would be 314.16.

  • You would just put in the radius and height in the cone volume formula which is πr²h 1/3

If this is a cylinder then the volume would be 942.48

  • Put in the radius and height in the cylinder volume formula which is πr²h
7 0
3 years ago
jenell wants to invest $5800 in a savings account that pays 6.6% simple interest. how long will it take for this investment to d
solong [7]
30.35 years so 31 years
5 0
3 years ago
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
Read 2 more answers
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