Answer:
158g
Explanation:
To calculate the "weight" (mass) of ethyl alcohol, we have to use this formula:
- Density will have units of gmL when dealing with a liquid or units of gcm3 when dealing with a solid.
The mass has units of grams, g.
The volume will have units of mL or cm3
We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:
density×volume=massvolume×volume
Density×Volume = Mass
0.789gmL×200.0mL
Thus, ethyl alcohol weighs 158g.
False
Explanation:
A molecule containing two or more polar bonds in its entire structure is a polar molecule. What determines the polarity of bonds in molecules their net dipole moment.
- In elements combination, the electronegativity difference between two atoms determines polarity.
- In a bonded specie, polarity of a molecule is determined by the net dipole moment.
- The net dipole moment depends on the geometry of the molecule.
- If the geometry favors the formation of polar bonds, the molecule will be polar.
Learn more:
Polarity brainly.com/question/2615067
water molecule brainly.com/question/11878570
#learnwithBrainly
A sodium ion has a charge of +1
A chlorine ion has a charge of -1
These ions are bonded by electrostatic forces, by the principles rule that all opposites attract. So it looks like a one Na atom bonded to one Cl atom. Like a double scoop ice cream that's not stacked
When electrons in atom interaction with light or photons one of the two process takes place:
1) they can absorb photons of a characteristic wavelength (which depends on the energy difference between two interacting atomic levels) and get excited to a higher energy level
2) or they can jump to a lower energy level and emit photons of the corresponding wavelength.
The type of spectrum produced when electrons in an atom undergo transitions to various levels by absorbing or emitting photons is termed as atomic spectrum.
(57.0 g B2O3 / (69.6202 g B2O3/mol) x (4mol BCI3 / 2 mol B2O3) = 1.64 mol BC13
(44.7 g C12) / (70.9064 g C12/mol) x (4mol BCI3 / 6mol C12) = 0.42027 mol BC13
(68.8 g C) / (12.01078 G C/mol) x (4mol BCI3 / 3 mol C) = 7.63 mol BCI3
C12 is the limiting reactant.
(0.42027 mol BCI3) X (117 . 170 g BCI3/mol) = 49.2 g BCI3 in theory.
