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saw5 [17]
3 years ago
5

What effect does increasing the concentration of a dissolved solute have on each of the colligative properties?

Chemistry
1 answer:
Igoryamba3 years ago
7 0

Answer:

If we increase the concentration of a dissolved solute, the solution would have a vapor pressure so much low, the boiling temperature for the solution will be so high, freezing point for the solution will be so much low and the osmotic pressure will be higher.

Colligative properties always depends on dissolved particles (solute)

Explanation:

These are the colligative properties

- Vapor pressure lowering

ΔP = P° . Xm

Vapor pressure of pure solvent - Vapor pressure of solution.

If we add more solute, it would raise the Xm, so the solution would have a vapor pressure so much low.

Vapor pressure pure solvent - Vapor pressure solution ↑ = P° . Xm ↑

- Boiling point elevation

ΔT = Kb . m

When we add more solute, we are increasing the molality.

↑T° boiling of solution - T° boiling pure solvent = Kf . m ↑

Boiling temperature for the solution will be so high.

- Freezing point depression

When we add more solute, we are increasing the molality.

ΔT = Kf . m

T° fussion of pure solvent - ↓T° fussion of solution = Kf . m↑

Freezing point for the solution will be so much low.

- Osmotic pressure

π = M . R . T

When we add solute, molarity is increasing. Therefore the osmotic pressure will be higher.

π↑ = M↑ . R . T

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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:2.8 × {10}^{-5}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \dfrac{2.36 \times 10 {}^{ - 2} }{8.4  \times {10}^{2} }

\qquad \tt \rightarrow \:  \dfrac{2.36  }{8.4   } \times  \cfrac{10 {}^{ - 2} }{10 {}^{2} }

\qquad \tt \rightarrow \:  0.28 \times 10 {}^{ - 2 - 2}

\qquad \tt \rightarrow \:  0.28  \times 10 {}^{  - 4}

\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
1 year ago
The energy released by a nuclear fusion reaction is produced when
Igoryamba

Answer:

2

Explanation:

energy produced in nuclear fusion or even fission is due to mass defect and it can be calculated by Einstein equation e=mc2

8 0
3 years ago
If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

Answer:30 L

Explanation:

Initial Volume

=

V

1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

K

Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

⇒

V

2

=

V

1

⋅

T

2

T

1

=

60

⋅

273

546

=

60

2

=

30

l

i

t

e

r

⇒

V

2

=

30

l

i

t

e

r

Hence the new volume of the gas is

30

l

i

t

e

r

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3 years ago
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