The cold air increases pressure on the basketball, causing it to appear flat. When it warms up that pressure is taken off, so the basketball is at it's normal state.
Answer:
The time spent in air by the car is 2.19 s
The height of the cliff is 58.5 m
Explanation:
Given;
initial velocity of the car, u = 16 m/s
horizontal distance traveled, R = 35 m
The horizontal distance or range of a projectile is given as;
R = vt
where;
t is the time spent in air by the projectile
t = R/v
t = 35 / 16
t = 2.19 s
The height of the cliff is given as;
h = ut + ¹/₂gt²
h = (16 x 2.19) + ¹/₂(9.8)(2.19)²
h = 58.5 m
Answer:A because they are both weak forces
Explanation:because they are weak forces
In both graphs, speed will be measured in meters/second.
In graph A, the object travelled a distance of 40 meters in 4 seconds
In graph B, the object is at rest for 5 seconds.
These are the correct answers
Answer:
magnitude of net magnetic field at given point is
![B = 5 \times 10^{-6} T](https://tex.z-dn.net/?f=B%20%3D%205%20%5Ctimes%2010%5E%7B-6%7D%20T)
Explanation:
As we know that magnetic field due to a long current carrying wire is given as
![B = \frac{\mu_o i}{2\pi r}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu_o%20i%7D%7B2%5Cpi%20r%7D)
here we we will find the magnetic field due to wire which is along x axis is given as
![i = 30 A](https://tex.z-dn.net/?f=i%20%3D%2030%20A)
r = 2 m
now we have
![B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}](https://tex.z-dn.net/?f=B_1%20%3D%20%5Cfrac%7B4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%20%2830%29%7D%7B2%5Cpi%20%282m%29%7D)
into the plane
Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as
![i = 40 A](https://tex.z-dn.net/?f=i%20%3D%2040%20A)
r = 2 m
now we have
![B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}](https://tex.z-dn.net/?f=B_2%20%3D%20%5Cfrac%7B4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%20%2840%29%7D%7B2%5Cpi%20%282m%29%7D)
along + x direction
Since the two magnetic field is perpendicular to each other
So here net magnetic field is given as
![B = \sqrt{B_1^2 + B_2^2}](https://tex.z-dn.net/?f=B%20%3D%20%5Csqrt%7BB_1%5E2%20%2B%20B_2%5E2%7D)
![B = 5 \times 10^{-6} T](https://tex.z-dn.net/?f=B%20%3D%205%20%5Ctimes%2010%5E%7B-6%7D%20T)