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Vera_Pavlovna [14]
3 years ago
11

You are presented with several wires made of the same conducting material. The radius and drift speed are given for each wire in

terms of some unknown units \rm r and \rm v. Rank the wires in order of decreasing electron current.Rank from most to least electron current.a) radius=3r, drift speed=1vb) radius=4r, drift speed=0.5vc) radius=1r, drift speed=5vd) radius=2r, drift speed=2.5v
Physics
1 answer:
jekas [21]3 years ago
3 0

\begin{array}{ccc}&\text{Radius} & \text{Drift Speed}\\d) & 2 \; r &2.5 \; v\\a) & 3 \; r &1 \; v\\b) & 4 \; r &0.5 \; v\\c) & 1 \; r &5 \; v\\\end{array}

<h3>Explanation</h3>

I = v \cdot A \cdot n \cdot q,

where

  • I is the current;
  • v is the drift speed;
  • A is the cross-section area of the wire,
  • n is the number of charge carrier per unit volume, and
  • q is the charge on each charge carrier.

Area of a circular cross-section:

A = \pi \cdot r^{2},

where

  • r is the radius of the wire.

n and q are the same for all four samples, for they are made out of the same material.

As a result, I of each wire is directly proportional to v \cdot r^{2} where the value of \pi \cdot n \cdot q is constant.

For each of the four wires:

\begin{array}{ccc|c}\\& r & v &I \propto v\cdot r^{2}\\a) & 3 & 1 & 9\\b) & 4 & 0.5 & 8\\c) & 1 & 5 & 5\\d) & 2 & 2.5 & 10\\\end{array}.

How do the four wires rank by their current?

d > a > b > c.

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lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

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Magnitude of vector is

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|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

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3 years ago
What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?
swat32

The car's velocity is (distance + direction) / (time) =

                                 (75 km-north) / (1.5 hrs)  =

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The number of neutrons is equal to the atomic number<br> O A True<br> B. False
jonny [76]

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A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is paralle
djverab [1.8K]

Answer:

a. 7.046 Nm²/C

b. 2.348 Nm²/C

Explanation:

Data given:

Base of equilateral triangle = 25.0 cm = 0.25 m

Strength of electric field = 260 N/C

In order to find the electric flux we first have to find out the area of triangle.

Area of triangle = \frac{\sqrt{3} }{4} a^{2}

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Lets find electric flux,

      Electric Flux = E. A

                          = 260×0.0271

                          = 7.046 Nm²/C

Now we can find the electric flux through each of the three sides.

Electric flux through three sides = \frac{7.046}{3}

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Answer:

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Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

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Where L is the length of the string and v the velocity of propagation. Use this expression to find the value of v.

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Where \mu is the desirable variable of the problem, the linear mass density, and T is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

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