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jarptica [38.1K]
4 years ago
14

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

{j} \left( 1 2 \sin^{3} t \right \mathbf{k}, 0 \leq t \leq \frac{\pi}{2} and f is the radial vector field \mathbf{f} \left( x, y, z \right = x \mathbf{i} y \mathbf{j} z \mathbf{k}, compute the work done by f on a particle moving along c
Mathematics
1 answer:
jonny [76]4 years ago
6 0
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
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Explanation:

2/3y+1=1/6y+8
Multiply both sides of the equation by 6 you get
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4y+6=y+48
Move variable to the left side and change its sign
4y-y+6=48


4y-y=48-6
Collect like terms
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Divide both sides of the equation by 3 and your final answer is
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You’re answer is: y=14 :)


8 0
3 years ago
In ΔEFG, the measure of ∠G=90°, FG = 4.8 feet, and GE = 3.5 feet. Find the measure of ∠F to the nearest degree.
taurus [48]

Answer:

36

Step-by-step explanation:

What function uses the ADJACENT and the OPPOSITE?

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\tan F = \frac{\text{opposite}}{\text{adjacent}}=\frac{3.5}{4.8}

tanF=

adjacent

opposite

​

=

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​

\tan F = \frac{3.5}{4.8}

tanF=

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3.5

​

F=\tan^{-1}(\frac{3.5}{4.8})

F=tan

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5 0
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otez555 [7]

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180 seconds is equal to 3 minutes because there is 60 seconds in a minute and 60 times 3 is 180

Step-by-step explanation:

So if it needs to be 180 seconds MORE than 3 minutes it would be 6 minutes

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