Answer:
Matrix transformation = ![\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)
Step-by-step explanation:
Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be:
.
To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:
P'=
= (5,-2)
Q'=
= (6,-3)
R'=
= (2,-3)
Answer:
area of circle=πr²=3.14×5²=78.5unit²
The slop of the line that is represented by the equation -5x + 2y = 10 is
Answer:
The Answer is: y = 2x - 3
Step-by-step explanation:
Given points: (3, 3) and (4, 5)
Find the slope, m:
m = y - y1/(x - x1)
m = 3 - 5/(3 - 4)
m = -2/-1 = 2
Use the Point Slope form of the equation:
y - y1 = m(x - x1)
y - 5 = 2(x - 4)
y - 5 = 2x - 8
y = 2x - 8 + 5
y = 2x - 3
Proof:
f(3) = 2(3) - 3
= 6 - 3 = 3, giving (3, 3)
Answer:
6 units
Step-by-step explanation:
(-4 , -10) ; (-4 , -4)
Distance = 
![= \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%28-4-%5B-4%5D%29%5E%7B2%7D%2B%28-4-%5B-10%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B%28-4%2B4%29%5E%7B2%7D%2B%28-4%2B10%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%286%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B36%7D%5C%5C%5C%5C%3D%206)