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1 year ago

I need help with this

Mathematics

2 answers:

kolbaska11 [484]1 year ago

6 0

Answer:

the answer is 3 because I just did that problem and I got the answer right

Aliun [14]1 year ago

5 0

Answer:

use air math it will give u full explanation

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Find the quotient. 800 ÷ 4

Art [367]

Answer:

200

Step-by-step explanation:

Hopw this helps! <3

3 0

2 years ago

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Mrs. Holt writes the expression 6/4 + 5/8 . She ask her students to simplify the expression and write the answer as a percentage

Oksanka [162]

Answer:

I don't see the table, but if you do 6/4 + 5/8 = 12/8+5/8 = 17/8.

17/8 = 2.125 = 212.5%

Step-by-step explanation:

3 0

2 years ago

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Brain boggling boggle help pls<br>:)<br>

MArishka [77]

Just write some random reason for your random answer and that should do it

8 0

1 year ago

What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 4y + 4=0

Sloan [31]

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - a coordinates of the center

r - a radius

$x^2+y^2-6x+4y+4=0\ \ \ |-4\\\\x^2-2\cdot x\cdot3+y^2+2\cdot y\cdot2=-4\ \ \ |+3^2\ |+2^2\\\\\underbrace{x^2-2\cdot x\cdot3+3^2}_{(a-b)^2=a^2-2ab+b^2}+\underbrace{y^2+2\cdot y\cdot2+2^2}_{(a+b)^2=a^2+2ab+b^2}=-4+3^2+2^2\\\\(x-3)^2+(y+2)^2=3^2$

Answer:

the center: (3, -2)

the radius: 3

5 0

2 years ago

A researcher believes that 12% of a simple random sample of adults will be able to identify a Toyota Scion by brand and model na

DochEvi [55]

Answer: 650

Step-by-step explanation:

When prior estimate of population proportion is known , then the formula to find the required sample size is given by :-

$n=p(1-p)(\dfrac{z^*}{E})^2$

, where p= population proportion

E= margin of error

z* = Critical value.

Let p be the proportion of adults able to identify a Toyota Scion by brand and model name.

As per given , we have

p = 12%= 0.12

E= 2.5%=0.025

Critical value for 95% confidence interval : z* = 1.960 [By z-table ]

Then, the required sample size = $n=(0.12)(1-(0.12))(\dfrac{1.96}{0.025})^2$

$n=(0.1056)(78.4)^2$

$n=(0.1056)(6146.56)$

$n=649.076736\approx650$

Thus , the required sample size = 650

6 0

2 years ago