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Radda [10]
3 years ago
9

A dolphin jumped up out of the water and back into the water in a parabolic path. (H) height (t) seconds . H=-8(t-0.5)^2+2 . How

long will the dolphin be in the air?
Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

4 seconds

Step-by-step explanation:

using the vertex formula of a quadratic,

a(x-h)^{2} + k, where (h,k) is the vertex

h = -8(t-0.5)^{2}+2    h is height and t is time in seconds

the vertex (maximum height) of the dolphin is (h,k) or (0.5, 2)  

Height of 1/2

time of 2 seconds

it will take 2 additional seconds to reach the water again.

this can also be solved using quadratic equation, but since it was already set up in vertex form, i'd use that.

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S_A_V [24]

Answer:

43.01

Step-by-step explanation:

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WILL MARK BRAINLIEST
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Answer:

a² + b² = 68

a3 + b3 = 520

Step-by-step explanation:

Given :

a + b = 10 (1)

ab = 16 (2)

A. Find a² + b²

(a + b)² = a² + 2ab + b² (3)

Substitutite the values of (1) and (2) into (3)

(10)² = a² + 2(16) + b²

100 = a² + 32 + b²

Subtract 32 from both sides

100 - 32 = a² + b²

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5 0
3 years ago
Please can I have an explanation also, I am terrible at these kinds of questions!
wlad13 [49]

Answer:

<em>The fraction of the beads that are red is</em>

Step-by-step explanation:

<u>Algebraic Expressions</u>

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

\displaystyle \frac{r}{r+y+b}       \qquad\qquad    [1]

Knowing that:

\displaystyle \frac{r}{y}=\frac{2}{3}      \qquad\qquad    [2]

\displaystyle \frac{y}{b}=\frac{5}{4}

Multiplying the equations above:

\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}

Simplifying:

\displaystyle \frac{r}{b}=\frac{5}{6}       \qquad\qquad    [3]

Dividing [1] by r:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}

Substituting from [2] and [3]:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}

Operating:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}

The fraction of the beads that are red is \mathbf{\frac{10}{37}}

8 0
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Answer:

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