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3 years ago

Evaluate the limit numerically or state that the limit does not exist. lim x → 0 (4x − 1)/ x

Mathematics

1 answer:

DENIUS [597]3 years ago

6 0

Answer:

As x ---> 0 - f(x) ---> ∞

As x ----> 0+ f(x) ---> -∞

Step-by-step explanation:

There is an asymptote in the graph of this function at x = 0.

As x approaches 0 from negative values of x the function approaches positive infinity.

AS x approaches 0 from positive values of x the function approaches

negative infinity .

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ikadub [295]

Answer:

Step-by-step explanation:

1) a = x - 5

a) z = y + 5

b) z = y - 3

c) z = 6y

d) z = 6y - 2

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5 0

3 years ago

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liberstina [14]

Answer:

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8 0

3 years ago

Mrs.smith paid $125 to have her hair colered and cut.if she tips her hairdresser 15% of her bill how much was the tip

rewona [7]

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5 0

3 years ago

In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95

Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval = (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0

3 years ago

Find the distance from the point (4,2) to the point (0,1).

vagabundo [1.1K]

Answer:

4.123 units

Step-by-step explanation:

Data provided:

Coordinates of point 1 as ( 4 , 2)

and,

Coordinates of point 2 as ( 0 , 1 )

Now,

The distance between the two point whose coordinates are given is calculated using the formula as:

distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

on substituting the values, we get

distance = $\sqrt{(0-4)^2+(1-2)^2}$

distance = $\sqrt{(-4)^2+(-1)^2}$

distance = $\sqrt{16+1}$

Distance = √17 = 4.123 units

6 0

3 years ago