4.0
.40
.040
Sorry if im wrong but im sure the second one is correct
Let x = amount of 70% juice we use.
Then 60-x = amount of 85% juice we'll use.
We'll set up an equation that is based on how much pure juice comes from each component and how much we need in the final mixture.
So 70% of x plus 85% of (60-x) must equal 80% of 60, or...
0.7x + 0.85(60-x) = 0.8(60)
0.7x + 51 - 0.85x = 48
-0.15x + 51 = 48
-0.15x = -3
x = 20
Then 60 - x = 60 - 20 = 40
Check: 70% of 20 pints = 14 pints of pure juice.
85% of 40 pints = 34 pints of pure juice
That's 48 pints of pure juice in the mix, which matche 80% 0f 60 pints.
You'd need 20 pints of the 70% juice and 40 pints of the 85% juice.
Answer:
2 - i
Step-by-step explanation:
If i in the expression f(i) is an imaginary number, then
f(i) = i^3 - 2 i^2 = -i - 2*(-1) = 2 - i
√<span>108x^5y^6
First, break up </span><span>√108 :
</span>√108 = √4 x √27 = 2 x √3 x √9 = 2 x √3 x 3 = 6<span>√3
</span><span>Since the x^5 is under a root of 2, that means we can take out an x^2 and leave one x under the radical :
</span>√x^5 = x^2 (<span>√x)
</span><span>Since the y^6 is raised to an even power and the root is even (2), that means we can take out all of the y's without leaving any under the radical :
</span><span>√y^6 = y^3
</span><span>Now, combine all of our simplified forms into one expression:
6x^2y^3</span><span>√3x</span><span>
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