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3 years ago

Help me with this question

Mathematics

1 answer:

SashulF [63]3 years ago

3 0

Answer:

15/4

Step-by-step explanation:

The formula for slope is:

(y₂-y₁)/(x₂-x₁)

Now we plug in the coordinates given to us into the equation:

(5-(-10))/(-1-(-5))

15/4

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Find the value of x to the nearest tenth!

sergij07 [2.7K]

Answer:

5.7

Step-by-step explanation:

sine cosine tangent

soh cah toa

sine = opposite/hypotenuse

so sin(35)= x/10

you can multiply 10 to both sides to get rid of the 10 denominator on the right leaving you with 10sin(35)=x

be sure your calculator is in degrees.

put that into a calculator leaving you with 5.7

5 0

3 years ago

Suppose you inherited a house that was purchased in 1950 for 20,000. It is now 2015 and the value of the house has increased by

Masja [62]

Answer:

I think the house would now costs $85,000

Step-by-step explanation:

First, I multiplied by how many years between 1950 to 2015 and 5 to get 325.

Next, I divided 20,000 by 100 to get 200 to find 1% of 20,000.

Then, I multiplied 325 by 200 to get 65,000

Finally, I added 20,000 to 65,000 to get 85,000

So, I guess/answer is $85,000

If I was wrong, then just say, "Sorry, but that was incorrect."

5 0

3 years ago

Read 2 more answers

For a process, the average range for all samples was 5 and the process average was 25. If the sample size was 10, calculate UCL

alexira [117]

Answer:

8.885

Step-by-step explanation:

Given that :

Sample size, n = 10

The average range, Rbar for all samples = 5

The upper control limit, UCL for the R-chart is :

UCL L= D4Rbar

From the control chart constant table, D4 = 1.777

Hence,

UCL = 1.777 * 5

UCL = 8.885

The UCL for the R-chart is 8.885

7 0

3 years ago

Use the formula to evaluate the series 1+2+4+8+...a10

valina [46]

Answer:

The sum of the given series is 1023

Step-by-step explanation:

Geometric series states that a series in which a constant ratio is obtained by multiplying the previous term.

Sum of the geometric series is given by:

$S_n = \frac{a(1-r^n)}{1-r}$

where a is the first term and n is the number of term.

Given the series: $1+2+4+8+.................+a_{10}$

This is a geometric series with common ratio(r) = 2

We have to find the sum of the series for 10th term.

⇒ n = 10 and a = 1

then;

$S_n = \frac{1(1-2^{10})}{1-2} =\frac{1-1024}{-1} =\frac{-1023}{-1}=1023$

Therefore, the sum of the given series is 1023

8 0

3 years ago

Listed below are the numbers of heroic firefighters who lost their lives in the United States each year while fighting forest fi

Marysya12 [62]

Answer:

Step-by-step explanation:

Hello!

Data

Year/Firefighters

2000: 20

2001: 18

2002: 23

2003: 30

2004: 20

2005: 12

2006: 24

2007: 9

2008: 25

2009: 15

2010: 8

2011: 11

2012: 15

2013: 34

Common measures of variation

Variance

S²= $\frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]$

∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34

∑X= 264

∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²

∑X²= 5770

n= 14

S²= $\frac{1}{13}[5770-\frac{(264)^2}{14} ]$

S²= 60.90

Standard deviation

The standard deviation is the square root of the variance

S= √S²= √60.90= 7.80

Coefficient of variation

Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.

C.V.= $\frac{S}{X[bar]}$ *100 = $\frac{7.80}{18.86}$ *100= 41.36%

The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.

X[bar]= ∑X/n= 264/14= 18.86

Range

In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.

R= Xmax - Xmin= 34 - 8= 26

Xmax= 34

Xmin= 8

Inter Quartile Range

Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.

IQR= C₃ - C₁= 23.5 - 11.5 = 12

Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.

Pos1: n/4= 14/4= 3.5

The first quantile is the number between position 3 and position 4

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₁= (11+12)/2= 11.5

Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.

Pos3: n*3/4= 14*3/4= 10.5

The third Quantile is between position 10 and 11

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₃= (23+24)/2= 23.5

The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.

I hope it helps!

6 0

3 years ago

Help me with this question ​

Help me with this question