Answer : The energy released is -3319.7 KJ.
Solution : Given,
Mass of methane = 59.7 g
Molar mass of methane = 16 g/mole
The value of 
is in negative that means the energy is releasing.
First we have to calculate the moles of methane.
Moles of methane = 
Now we have to calculate the amount of energy released.
The given reaction is,
From the reaction, we conclude that
1 mole of methane releases -890 KJ/mole of energy
3.73 moles of methane releases 
of energy
Therefore, the energy released is -3319.7 KJ.
Answer:
b. the rate of destruction is equal to the rate of carbonate input.
Explanation:
At the Calcite Compensation Depth(CCD) the rate of addition of calcite and dissolution of the mineral is the same. Below this depth, all calcite minerals are dissolved.
The CCD occurs at a depth of 3000-4000m. It varies from places to places within the ocean. Other factors play important roles in determining the CCD. Some of the factors are temperature and pressure.
Answer:
e. I, At
Explanation:
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In this case, since the periodic trends of a series of elements belonging to the same group towards physical and chemical properties tend to be the same when closer in period, we notice that Mg and Al, Br and Kr and As and Br are close but in period, not in the same group; therefore e. I, At, iodine and astatine, are going to tend to exhibit the greatest similarity in their physical and chemical properties.
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Depression can affect a person psychologically, it also has the potential to affect physical structures in the brain. These physical changes range from inflammation and oxygen restriction, to actual shrinking. Depression can impact the central control center of nervous system. Depression can cause amygdala to enlarge. This is a part of the brain associated with emotional responses. When amygdala becomes larger and more active, it causes sleep disturbances, changes in activity levels, and changes in other hormones.
Answer:
3 Cu + 8 HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
Explanation:
Make sure both sides are equal
3 <u>Cu</u> + 8 H<u>N</u>O3 --> 3 <u>Cu</u>(NO3)2 + 2 <u>N</u>O + 4 H2O
// start by those elements that change their oxidation degree
<u>Cu</u> and <u>N</u>
// also you can write reduction-oxidation reactions
+ 2 
--> 
| 2
- 3 --> 
| 3
// write the numbers of electrons that are lost/gained as the coefficients of the opposite elements
// then check if H and O are the same on both sides
// adjust if they aren't.
