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Serjik [45]
3 years ago
14

When copper(II) oxide is heated with hydrogen gas, water and copper metal is produced. What mass of copper can be obtained if 32

.0g of copper(II) oxide is used?
A: 24.3g
B: 25.5g
C: 27.6g
Chemistry
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

25.5 g

Explanation:

First, you will need a balanced chemical equation

CuO  +  H₂  ==>  H₂O  +  Cu

From the equation above, we can see that for every 1 mole of CuO (copper(II) oxide), 1 mole of Cu (copper) is produced.  

Convert grams of CuO to moles.  You should get 0.402 mol.  Now with the relationship established above, you can see that you should ideally get 0.402 mol.  Convert this to grams.  Your answer should be 25.5 g.

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How many atoms are in 3.89 moles of Cu?
AleksandrR [38]

Answer:

2.34×10^24

Explanation:

N=n×Na

N=3.89×(6.02×10^23)

N=2.34×+0^24 atoms of Cu

3 0
4 years ago
A chemist prepares a solution of silver(II) oxide by measuring out 0.0013 of silver(II) oxide into a 100 mL volumetric flask and
azamat

Answer:

1.3x10⁻⁸ mol/L

Explanation:

<em>0.0013μmol, Calculate concentration in mol/L</em>

<em />

To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:

<em>Moles silver(II) oxide:</em>

0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles

<em>Liters solution:</em>

100mL * (1L / 1000mL) = 0.1L

That means concentration in mol/L is:

1.3x10⁻⁹ moles / 0.1L =

<h3>1.3x10⁻⁸ mol/L</h3>
6 0
3 years ago
The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
Which ions remain in solution after pbi2 precipitation is complete? express your answers as ions separated by a comma?
olga nikolaevna [1]

Answer;

K+ and NO3- ions

Explanation;

The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.

However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.

7 0
4 years ago
What is mole concept and muscular mass
Fantom [35]

the mole concept :

a mole (mol) is defined as the amount of substance that contains as many atoms, molecules, icons, electrons or any other elementary entities as there are carbon atoms in exactly 12 gm of. the number of atoms in 12gm of is called Avogadro's number.

I'm not sure about muscular mass sorryyyy

6 0
3 years ago
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