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vesna_86 [32]
3 years ago
14

18. One number is 3 less than a second number. Twice the second number is 12 more than 3 times the first.

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer: The numbers are -3 and - 6

Step-by-step explanation:

Let the first number be x and the second number be y , then from the first statement we have

x + 3 = y  ............. equation 1

From the second statement

2y  = 3x + 12 ............ equation 2

solving the resulting simultaneous equation by substitution method ,we have:

substitute x - 3= y  into equation 2 , we have

2( x + 3) = 3x + 12

2x + 6 = 3x +  12

2x - 3x = 6

x = -6

substitute x = - 6 into equation 1 , that is

- 6 + 3 = y

Therefore ,

y = -3

2y = 3y + 3

Check:

x + 3 = y , implies

-6 + 3 = -3 = y

Also 2y = 3x + 12 , implies

2(-3) = -6

3(-6) + 12 = -6

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\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
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a_4&-4096rrr\\
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\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
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