Answer:
Mechanic 1: $55 per hour
Mechanic 2: $105 per hour
Step-by-step explanation:
Given
Represent the rate of the first mechanic with x and the second with y.
So, we have:

The total earnings is: $1850, so we have:

Required
Determine the rate of each
The equations are:
--- (1)
--- (2)
Divide (2) through by 5
--- (3)
Subtract (1) from (3)


Divide through by 2


Substitute 105 for y in (1)

Make x the subject

Substitute 105 for y


Hence:
Mechanic 1: $55 per hour
Mechanic 2: $105 per hour
Answer:
compare (1/2)^3 is greater than (a/b)^2
Step-by-step explanation:
1/2*1/2*1/2= 0.125 or 1/8
1/4 * 1/4=0.0625 or 1/16
ANSWER:
x = 10 / 3
y = 0
STEP-BY-STEP EXPLANATION:
We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.
Equation No. 1 -
- 6x - 14y = - 20
Equation No. 2 -
- 3x - 7y = - 10
First, we will make ( x ) the subject in the first equation and simplify accordingly.
Equation No. 1 -
- 6x - 14y = - 20
- 6x = - 20 + 14y
x = ( - 20 + 14y ) / - 6
x = ( - 10 + 7y ) / - 3
From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.
Equation No. 2 -
- 3x - 7y = - 10
- 7y = - 10 + 3x
- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]
- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]
- 7y = - 10 + ( 10 - 7y )
- 7y = - 7y
- 7y + 7y = 0
0y = 0
y = 0
Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.
x = ( - 10 + 7y ) / - 3
x = [ - 10 + 7 ( 0 ) ] / - 3
x = [ - 10 + 0 ] / - 3
x = - 10 / - 3
x = 10 / 3
Answer:
Sales are (increasing/decreasing)…. _____….(purchases, purchases/month, months/purchases, $/purchases, purchases/$, $, months)
D. (January, February, March, April, May, June, July, August, September, October, November, December)
Answer:
(See explanation for further details)
Step-by-step explanation:
The real expression is:

The general equation for the second-order polynomial is:

This condition must be observed for the case of a quadratic equation with equal roots:



