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lorasvet [3.4K]
3 years ago
7

What are the intercepts of f(x)=(3x-4)(7x+2)

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

1. (-0,286; 0), (1,333; 0)

2. (0; -8)

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Two mechanics worked on the car the first mechanic work for five hours in a sec mechanic work for 15 hours together the tires a
FrozenT [24]

Answer:

Mechanic 1: $55 per hour

Mechanic 2: $105 per hour

Step-by-step explanation:

Given

Represent the rate of the first mechanic with x and the second with y.

So, we have:

x + y = 160

The total earnings is: $1850, so we have:

5x + 15y = 1850

Required

Determine the rate of each

The equations are:

x + y = 160 --- (1)

5x + 15y = 1850 --- (2)

Divide (2) through by 5

x + 3y = 370 --- (3)

Subtract (1) from (3)

x - x + 3y - y = 370 - 160

2y = 210

Divide through by 2

y = \frac{210}{2}

y = 105

Substitute 105 for y in (1)

x + y = 160

Make x the subject

x = 160 - y

Substitute 105 for y

x = 160 - 105

x = 55

Hence:

Mechanic 1: $55 per hour

Mechanic 2: $105 per hour

7 0
3 years ago
Please do this ASAP! Due tomorrow. 9:12pm here.
Mumz [18]

Answer:

compare (1/2)^3 is greater than (a/b)^2

Step-by-step explanation:

1/2*1/2*1/2= 0.125 or 1/8

1/4 * 1/4=0.0625 or 1/16

8 0
3 years ago
-6x-14y=-20<br> -3x-7y=-10
Alex Ar [27]
ANSWER:

x = 10 / 3

y = 0

STEP-BY-STEP EXPLANATION:

We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.

Equation No. 1 -

- 6x - 14y = - 20

Equation No. 2 -

- 3x - 7y = - 10

First, we will make ( x ) the subject in the first equation and simplify accordingly.

Equation No. 1 -

- 6x - 14y = - 20

- 6x = - 20 + 14y

x = ( - 20 + 14y ) / - 6

x = ( - 10 + 7y ) / - 3

From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.

Equation No. 2 -

- 3x - 7y = - 10

- 7y = - 10 + 3x

- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]

- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]

- 7y = - 10 + ( 10 - 7y )

- 7y = - 7y

- 7y + 7y = 0

0y = 0

y = 0

Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.

x = ( - 10 + 7y ) / - 3

x = [ - 10 + 7 ( 0 ) ] / - 3

x = [ - 10 + 0 ] / - 3

x = - 10 / - 3

x = 10 / 3
6 0
3 years ago
A. Sales are (increasing/decreasing)…. _____….(purchases, purchases/month, months/purchases, $/purchases, purchases/$, $, months
lord [1]

Answer:

Sales are (increasing/decreasing)…. _____….(purchases, purchases/month, months/purchases, $/purchases, purchases/$, $, months)

D. (January, February, March, April, May, June, July, August, September, October, November, December)

5 0
2 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
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