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kozerog [31]
2 years ago
6

Alvin has 25 coins that values $4.00, some are quarters and some are dimes. What is the ratio of the numbers of dimes to the num

ber of quarters.

Mathematics
2 answers:
NemiM [27]2 years ago
7 0

Since .25*10 is 2.50 and .10*15 is 1.50 it equals $4. So the ratio is 10:15 which turns to 2:3 ratio simplified.

Zarrin [17]2 years ago
7 0

Let x = # of quarters // Let y = the # of dimes

25x + 10y = 400

x + y = 25

Using these two equations, we can make a system to solve. The formatting on Brainly makes it hard to write on here, so I'll just handwrite it.

Basically, the answer is 3:2.

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Are there any other numbers to this question? I will be glad to help.

8 0
3 years ago
Choose the value for x that solves this equation. 0 = -2x + 6
lana66690 [7]

<em>Answer:</em>

<em>x = 3</em>

<em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>0 = - 2x + 6</em>

<em>2x = 6</em>

<em>x = 6 : 2</em>

<em>x = 3</em>

<em>Good luck !</em>

7 0
3 years ago
what is an equation of the line that is parallel to the line with y=-.60x+2 and passes through the point (10,-10)
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y = -0.60x - 4

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4 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
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